Interface和Abstract类中的方法相同 [英] Same method in Interface and Abstract class

问题描述

我遇到了这种情况：

public interface Intr {
    public void m1();
}

public abstract class Abs {
    public void m1() {
        System.out.println("Abs.m1()");
    }
    // public abstract void m1();
}

public class A extends Abs implements Intr {

    @Override
    public void m1() {
        // which method am I overriding, well it is Abs.m1() but why?
        // if method implemented is Abs.m1(), then why I am not getting error for Intr.m1() not implemented.
    }

}

推荐答案

您同时满足这两个条件;即。一个实现同时满足抽象类要求和接口要求。

You are satisfying both conditions at once; ie. the one implementation is at the same time fulfilling the abstract class requirements and the interface requirements.

作为注释，除非您使用 Intr 在另一个继承链中，你不需要它。此外，将实现Intr 移动到抽象类定义可能是有意义的。

As a note, unless you are using Intr in another inheritance chain, you don't need it. Also, it might make sense to move the implements Intr up to the abstract class definition.

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