如何使用Twitter4j检索超过100个结果 [英] How to retrieve more than 100 results using Twitter4j

问题描述

我正在使用Twitter4j库来检索推文，但我的目的并不足够。目前，我从一个页面获得最多100个。如何在处理中将maxId和sinceId实现为以下代码，以便从Twitter搜索API中检索超过100个结果？我对Processing（以及一般的编程）完全不熟悉，所以对此的任何方向都会很棒！谢谢！

I'm using the Twitter4j library to retrieve tweets, but I'm not getting nearly enough for my purposes. Currently, I'm getting that maximum of 100 from one page. How do I implement maxId and sinceId into the below code in Processing in order to retrieve more than the 100 results from the Twitter search API? I'm totally new to Processing (and programming in general), so any bit of direction on this would be awesome! Thanks!

void setup() {

  ConfigurationBuilder cb = new ConfigurationBuilder();
  cb.setOAuthConsumerKey("xxxx");
  cb.setOAuthConsumerSecret("xxxx");
  cb.setOAuthAccessToken("xxxx");
  cb.setOAuthAccessTokenSecret("xxxx");

  Twitter twitter = new TwitterFactory(cb.build()).getInstance();
  Query query = new Query("#peace");
  query.setCount(100);

  try {
    QueryResult result = twitter.search(query);
    ArrayList tweets = (ArrayList) result.getTweets();

    for (int i = 0; i < tweets.size(); i++) {
      Status t = (Status) tweets.get(i);

      GeoLocation loc = t.getGeoLocation();

      if (loc!=null) {
        tweets.get(i++);

        String user = t.getUser().getScreenName();
        String msg = t.getText();

        Double lat = t.getGeoLocation().getLatitude();
        Double lon = t.getGeoLocation().getLongitude();

        println("USER: " + user + " wrote: " + msg + " located at " + lat + ", " + lon);

      }
    }
  }

  catch (TwitterException te) {
    println("Couldn't connect: " + te);
  };
}

void draw() {
}

推荐答案

不幸的是，你不能，至少不能以直接的方式做到这一点

Unfortunately you can't, at least not in a direct way such as doing

query.setCount(101);

作为 javadoc 表示它最多只允许100条推文。

As the javadoc says it will only allow up to 100 tweets.

为了克服这个问题，您只需要批量询问它们，并且在每个批次设置中，您获得的最大ID比最后一个ID少1得到了最后一个。为了解决这个问题，你将每个推文从流程收集到一个ArrayList（顺便说一下，它不应该保持通用，但是它的类型定义为 ArrayList< Status> - 携带Status对象的ArrayList）然后打印所有内容！这是一个实现：

In order to overcome this, you just have to ask for them in batches and in every batch set the maximum ID that you get to be 1 less than the last Id you got from the last one. To wrap this up, you gather every tweet from the process into an ArrayList (which by the way should not stay generic, but have its type defined as ArrayList<Status> - An ArrayList that carries Status objects) and then print everything! Here's an implementation:

void setup() {

  ConfigurationBuilder cb = new ConfigurationBuilder();
  cb.setOAuthConsumerKey("xxxx");
  cb.setOAuthConsumerSecret("xxxx");
  cb.setOAuthAccessToken("xxxx");
  cb.setOAuthAccessTokenSecret("xxxx");

  Twitter twitter = new TwitterFactory(cb.build()).getInstance();
  Query query = new Query("#peace");
  int numberOfTweets = 512;
  long lastID = Long.MAX_VALUE;
  ArrayList<Status> tweets = new ArrayList<Status>();
  while (tweets.size () < numberOfTweets) {
    if (numberOfTweets - tweets.size() > 100)
      query.setCount(100);
    else 
      query.setCount(numberOfTweets - tweets.size());
    try {
      QueryResult result = twitter.search(query);
      tweets.addAll(result.getTweets());
      println("Gathered " + tweets.size() + " tweets");
      for (Status t: tweets) 
        if(t.getId() < lastID) lastID = t.getId();

    }

    catch (TwitterException te) {
      println("Couldn't connect: " + te);
    }; 
    query.setMaxId(lastID-1);
  }

  for (int i = 0; i < tweets.size(); i++) {
    Status t = (Status) tweets.get(i);

    GeoLocation loc = t.getGeoLocation();

    String user = t.getUser().getScreenName();
    String msg = t.getText();
    String time = "";
    if (loc!=null) {
      Double lat = t.getGeoLocation().getLatitude();
      Double lon = t.getGeoLocation().getLongitude();
      println(i + " USER: " + user + " wrote: " + msg + " located at " + lat + ", " + lon);
    } 
    else 
      println(i + " USER: " + user + " wrote: " + msg);
  }
}

注：行

ArrayList<Status> tweets = new ArrayList<Status>();

应该是：

List<Status> tweets = new ArrayList<Status>();

因为你应始终使用该接口，以防您想添加不同的实现。当然，如果你在Processing 2.x上，那么在开始时需要这个：

because you should always use the interface in case you want to add a different implementation. This of course, if you are on Processing 2.x will require this in the beginning:

import java.util.List;

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