类中的构造函数不能应用于给定类型 [英] Constructor in class cannot be applied to given types

问题描述

我使用数组得到以下代码来查找一些原始数字。但是，在尝试编译我的用户类PalindromeArrayUser时，它说 - 类中的构造函数不能应用于给定的类型

I ve got the following code using arrays to find some prim numbers. However, when trying to compile my user class PalindromeArrayUser it says - "Constructor in class cannot be applied to given types"

required：int。找到
：没有参数。
原因：实际和正式参数列表的长度不同。

required: int. found: no arguments. reason: actual and formal arguments lists differ in length.

但是，我已经将构造函数传递给了一个int值（就像它在我的设计中一样）蓝图）。我不太明白问题的来源。谢谢。

However, I have passed to the constructer an int value (the same way it was designed in my blueprint). I don't quite get where the problem comes from. Thanks.

这是我的两个班级

 public class PalindromeArray 
 {

int arrLength;

public PalindromeArray(int InputValue) 
{
    arrLength = InputValue;
}


int arr[] = new int[arrLength];
boolean check[] = new boolean [arrLength];


public void InitializeArray()  
{

    for (int k = 2; k < arr.length; k++)
    {
        arr[k] = k;
        check[k] = true;

    }   
}

public void primeCheck()  
{

    for (int i = 2; i < Math.sqrt(arr.length - 1); i++ )
    {
        if (check[i] == true)
        {
        for (int j = 2; j < arr.length; j++)
          {
            if (j % i == 0)
                {
                     check[j] = false;
                     check[i] = true;
                }
          }
        }   

    }   
}

public void PrintArray() 
{
    for (int k = 2; k < arr.length; k++)
    {
        if ((!check[k]) == false)
            System.out.println(arr[k]);

    }
}

   }

这是我的用户类，问题来自于此。上面的类编译得很好。

And this is my User class where the problem comes from. The class above compiles fine.

 import java.io.*;

 public class PalindromeArrayUser extends PalindromeArray
 {
public static void main(String argv[]) throws IOException 
{
    BufferedReader input = new BufferedReader(new InputStreamReader(System.in));

    System.out.println("Please enter the upper bound.");

    String line = input.readLine();

    int InputUser = Integer.parseInt(line);
                                     // this is where I pass the same int type as I  
                                                  // constructed it
    PalindromeArray palindrome = new PalindromeArray(InputUser);
    palindrome.InitializeArray();
    palindrome.primeCheck();
    palindrome.PrintArray();


}

 }

推荐答案

为类创建构造函数时，不会为该类创建任何默认构造函数。因此，如果你扩展该类，并且如果子类试图调用其超类的no-arg构造函数，则会出现编译时错误。

when you create a constructor for a class, there won't be any default constructor created for that class. so if you extend that class and if the subclass tries to call the no-arg constructor of its super class then there will be an compile-time error.

来演示：

class Parent {
  int i;
  public Parent(int i) {
    this.i=i;
  }
}

class Child extends Parent {
  int j;
  public Child(int i, int j) {
    super(i);
    this.j=j;
  }
  public Child(int j) {
    // here a call to super() is made, but since there is no no-arg constructor
    // for class Parent there will be a compile time error
    this.j=j;
  }
}

编辑：

回答你的问题，不要将值 arrLength 分配给 arr [] 和检查[] ，因为当时arrLength将是 0 。

to answer your question do this, don't assign the value arrLength to arr[] and check[] as arrLength would be 0 at that time.

所以只需要声明它们

int arr[];
boolean check[];

并在将输入分配给 arrLength 放这些陈述。

and in the constructor after you assign the input to arrLength put these statements.

arr = new int[arrLength];
check = new boolean [arrLength];

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