Java Long原始类型最大限制 [英] Java Long primitive type maximum limit

问题描述

我正在使用Long基元类型，只要我的'generateNumber'method调用，它就会递增1。如果Long达到他的最大限制会怎么样？会抛出任何异常还是会重置为最小值？
这是我的示例代码：

I am using the Long primitive type which increments by 1 whenever my 'generateNumber'method called. What happens if Long reaches to his maximum limit? will throw any exception or will reset to minimum value? here is my sample code:

class LongTest {
   private static long increment;
   public static long generateNumber(){
       ++increment;
       return increment;
   }
}

推荐答案

Long.MAX_VALUE 是 9,223,372,036,854,775,807 。

如果你正在执行你的功能是每纳秒一次，根据此来源。

If you were executing your function once per nanosecond, it would still take over 292 years to encounter this situation according to this source.

当发生这种情况时，它只会回绕到 Long.MIN_VALUE ，或 -9,223,372,036,854,775,808 正如其他人所说。

When that happens, it'll just wrap around to Long.MIN_VALUE, or -9,223,372,036,854,775,808 as others have said.

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