JavaFX：按行和列获取节点 [英] JavaFX: Get Node by row and column

问题描述

如果我知道它的位置（行和列）或从gridPane获取节点的任何其他方式，有没有办法从gridPane获取特定节点？

Is there any way to get a specific Node from a gridPane if I know its location (row and column) or any other way to get a node from a gridPane?

推荐答案

我没有看到任何直接的API来获取逐行列索引，但你可以使用 getChildren API来自窗格， getRowIndex（Node child）和 getColumnIndex（Node child） from GridPane

I don't see any direct API to get node by row column index, but you can use getChildren API from Pane, and getRowIndex(Node child) and getColumnIndex(Node child) from GridPane

//Gets the list of children of this Parent. 
public ObservableList<Node> getChildren() 
//Returns the child's column index constraint if set
public static java.lang.Integer getColumnIndex(Node child)
//Returns the child's row index constraint if set.
public static java.lang.Integer getRowIndex(Node child)

以下是示例代码使用 GridPane

public Node getNodeByRowColumnIndex (final int row, final int column, GridPane gridPane) {
    Node result = null;
    ObservableList<Node> childrens = gridPane.getChildren();

    for (Node node : childrens) {
        if(gridPane.getRowIndex(node) == row && gridPane.getColumnIndex(node) == column) {
            result = node;
            break;
        }
    }

    return result;
}

重要更新： getRowIndex（）和 getColumnIndex（）现在是静态方法，应该更改为 GridPane.getRowIndex（node）和 GridPane.getColumnIndex（节点）。

Important Update: getRowIndex() and getColumnIndex() are now static methods and should be changed to GridPane.getRowIndex(node) and GridPane.getColumnIndex(node).

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