如何在jpa中编写顺序并限制查询 [英] how to write order by and limit query in jpa

问题描述

可能重复：

使用JPA选择前1名结果

我希望当我写下以下查询时，根据我的表'MasterScrip'
的'totalTradedVolume'获取前10名结果：

i wish to fetch top 10 results based on 'totalTradedVolume' filed of my table 'MasterScrip' when i write the following query:

Collection<MasterScrip> sm=null;
   sm=em.createQuery("select m from MasterScrip m where m.type = :type order by m.totalTradedVolume limit 2").setParameter("type", type).getResultList();

我收到以下异常：

Caused by: java.lang.IllegalArgumentException: An exception occurred while creating a query in EntityManager: 
Exception Description: Syntax error parsing the query [select m from MasterScrip m where m.type = :type order by m.totalTradedVolume limit 2], line 1, column 78: unexpected token [limit].
Internal Exception: NoViableAltException(80@[])

我的jpa查询有问题。任何人都可以纠正我吗？

something's wrong with my jpa query. can anyone pls correct me?

推荐答案

限制在JPA中无法识别。您可以改为使用 query.setMaxResults 方法：

limit is not recognized in JPA. You can instead use the query.setMaxResults method:

sm = em.createQuery("select m from MasterScrip m where m.type = :type 
        order by m.totalTradedVolume")
    .setParameter("type", type)
    .setMaxResults(2).getResultList()

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