如何按字母顺序对字符串java进行排序 [英] how to sort a string alphabetically java

问题描述

我想按字母顺序对JAVA中的字符串进行排序，如下所示：
大写字母和小写字母后跟
AaBbCcDdEeFfGg。
例如，如果我把AbaC给我AabC
谢谢!!

I want to sort a string in JAVA alphabetically, as follows Capital letter and lowercase letter followed AaBbCcDdEeFfGg. for example if I put AbaC return me AabC thanks!!

推荐答案

你可以这样做 Arrays.sort ，如果您先将字符放入数组中。 （它必须是 Character 对象的数组，而不是 char 基元，以便使用自定义的不区分大小写的比较器。）

You can do this using Arrays.sort, if you put the characters into an array first. (It must be an array of Character objects rather than char primitives, in order to use a custom case-insensitive comparator.)

// put the characters into an array
Character[] chars = new Character[str.length()];
for (int i = 0; i < chars.length; i++)
    chars[i] = str.charAt(i);

// sort the array
Arrays.sort(chars, new Comparator<Character>() {
    public int compare(Character c1, Character c2) {
        int cmp = Character.compare(
            Character.toLowerCase(c1.charValue()),
            Character.toLowerCase(c2.charValue())
        );
        if (cmp != 0) return cmp;
        return Character.compare(c1.charValue(), c2.charValue());
    }
});

// rebuild the string
StringBuilder sb = new StringBuilder(chars.length);
for (char c : chars) sb.append(c);
str = sb.toString();

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