根据正则表达式拆分字符串 [英] Split a String based on regex

问题描述

我有一个字符串需要根据，（逗号）的出现进行拆分，但需要忽略一对括号中出现的任何字符串。
例如， B2B，（A2C，AMM），（BNC，1NF），（106，A01），AAA，AX3
应拆分进入

I have a string that needs to be split based on the occurrence of a ","(comma), but need to ignore any occurrence of it that comes within a pair of parentheses. For example, B2B,(A2C,AMM),(BNC,1NF),(106,A01),AAA,AX3 Should be split into

B2B,
(A2C,AMM),
(BNC,1NF),
(106,A01),
AAA,
AX3

推荐答案

FOR NON NESTED

,(?![^\(]*\))

FOR NESTED （括号内的括号）

(?<!\([^\)]*),(?![^\(]*\))

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