如何在java中对JSON对象进行排序？ [英] How to sort JSON object in java?

问题描述

我一直在寻找一段时间，想要一种方法来对这样的JSON对象进行排序：

I've been looking for a while and want a way to sort a JSON object like this:

{"results": [
  {
    "layerId": 5,
    "layerName": "Pharmaceutical Entities",
    "attributes": {
      "OBJECTID": "35",
      "FACILITYTYPE": "Pharmacy",
      "FACILITYSUBTYPE": "24 Hr Pharmacy",
      "COMMERCIALNAME_E": "SADD MAARAB PHARMACY"
      },
    "geometryType": "esriGeometryPoint",
   },
  {
    "layerId": 5,
    "layerName": "Pharmaceutical Entities",
    "attributes": {
      "OBJECTID": "1",
      "FACILITYTYPE": "Pharmacy",
      "FACILITYSUBTYPE": "24 Hr Pharmacy",
      "COMMERCIALNAME_E": "GAYATHY HOSPITAL  PHARMACY"
    },
    "geometryType": "esriGeometryPoint",
  },
     {
    "layerId": 5,
    "layerName": "Pharmaceutical Entities",
    "attributes": {
      "OBJECTID": "255",
      "FACILITYTYPE": "Pharmacy",
      "FACILITYSUBTYPE": "24 Hr Pharmacy",
      "COMMERCIALNAME_E": "AL DEWAN PHARMACY"
      },
    "geometryType": "esriGeometryPoint",
   }
]}

并按字母顺序按COMMERCIALNAME_E的值排序：

and sort is alphabetically by value of "COMMERCIALNAME_E" to get:

{"results": [
   {
    "layerId": 5,
    "layerName": "Pharmaceutical Entities",
    "attributes": {
      "OBJECTID": "255",
      "FACILITYTYPE": "Pharmacy",
      "FACILITYSUBTYPE": "24 Hr Pharmacy",
      "COMMERCIALNAME_E": "AL DEWAN PHARMACY"
      },
    "geometryType": "esriGeometryPoint"
   },
  {
    "layerId": 5,
    "layerName": "Pharmaceutical Entities",
    "attributes": {
      "OBJECTID": "1",
      "FACILITYTYPE": "Pharmacy",
      "FACILITYSUBTYPE": "24 Hr Pharmacy",
      "COMMERCIALNAME_E": "GAYATHY HOSPITAL  PHARMACY"
       },
    "geometryType": "esriGeometryPoint"
   },
   {
    "layerId": 5,
    "layerName": "Pharmaceutical Entities",
    "attributes": {
      "OBJECTID": "35",
      "FACILITYTYPE": "Pharmacy",
      "FACILITYSUBTYPE": "24 Hr Pharmacy",
      "COMMERCIALNAME_E": "SADD MAARAB PHARMACY"
      },
    "geometryType": "esriGeometryPoint"
   }
]}

我找不到任何可以执行此操作的代码。任何人都可以给我一些帮助吗？

I can't find any code that will do this. Can anyone give me some help?

推荐答案

将这些JSON解析为对象集合并使用比较器使用首选字段对其进行排序。

Parse these JSON to Collection of Objects and use comparator to sort it using your preferred field.

• 使用GSON将其解析为对象集合

• Use GSON to parse it to collection of objects

示例：

import com.google.gson.Gson;

class Person {
  private int age;
  private String name;
}

String json = "{'age':22,'name':'Jigar'}";
Gson gson = new Gson();
TestJsonFromObject obj = gson.fromJson(json, Person.class);  

如果你想从Object创建JSON。

If you want to create JSON from Object.

Person p = new Person();
p.setName("Jigar");
p.setAge(22);
String jsonStr = new com.google.gson.Gson().toJson(obj);

这篇关于如何在java中对JSON对象进行排序？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！