逃脱（正则表达式 [英] Escape ( in regular expression

问题描述

我正在搜索正则表达式 - 。（冲突副本。。我为此写了以下代码

Im searching for the regular expression - ".(conflicted copy.". I wrote the following code for this

String str = "12B - (conflicted copy 2013-11-16-11-07-12)";
boolean matches = str.matches(".*(conflicted.*");
System.out.println(matches);

但我得到了异常

线程main中的异常java.util.regex.PatternSyntaxException：索引附近的未闭合组15
。（冲突。

我知道编译器认为（是开头模式组。我试图通过添加 \（）来逃避（，但这不起作用。

I understand that the compiler thinks that ( is the beginning of a pattern group. I tried to escape ( by adding \( but that doesnt work.

有人可以告诉我如何逃避（这里？

Can someone tell me how to escape ( here ?

推荐答案

转义是由 \ 完成的。在Java中， \ 写成 \\ ¹ ，所以你应该逃避g （将是 \\（。

Escaping is done by \. In Java, \ is written as \\¹, so you should escaping the ( would be \\(.

旁注：最好看看 Pattern＃quote 返回一个文字模式字符串。在你的情况下，它没有那么有用，因为你不想逃避所有特殊字符。

Side note: It's good to have a look at Pattern#quote that returns a literal pattern String. In your case, it's not that helpful since you don't want to escape all special-characters.

¹ 因为前面带有反斜杠的字符（ \ ）是一个转义序列，并且具有特殊功能对编译器的意义。

¹ Because a character preceded by a backslash (\) is an escape sequence and has special meaning to the compiler.

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