如何从谷歌地图或地方API一个地方的图片 [英] How to get a picture of a place from google maps or places API

问题描述

我使用的是谷歌的地方API来检索有关地方的数据，但怎么也找不到让​​那个地方的图片，谷歌API的地方正好提供了图标，这是不一样的。我需要你的照片，当您搜索在谷歌地图的地方在网络浏览器为例。通常有来自Panoramio的更多的图片，但Panoramio的API只能搜索图片按位置，而不是由一个特定的餐馆或酒店名称，例如。任何想法？

I'm using Google Places API to retrieve data about places, but couldn't find how to get a picture of that place, Google Places API just provides icon which is not the same. I need the photo you get when you search for a place in Google Maps in a web browser for example. There is usually more pictures from Panoramio, but Panoramio API can only search for pictures by location and not by a particular restaurant or hotel name for example. Any ideas?

推荐答案

该API的地方会给你的坐标（经度和纬度）在的到位详细回应;那么你可以发送坐标到 Panoramio的API 。

The Places API will give you the coordinates (latitude and longitude) in the place detail response; you can then send the coordinates to the Panoramio API.

例如（在API文档的范例中）：

For example (drawing from examples in the API docs):

https://maps.googleapis.com/maps/api/place/details/json?reference=<big长键到位＆GT;＆放大器;传感器=真放大器;关键= AIzaSyAiFpFd85eMtfbvmVNEYuNds5TEF9FjIPI

响应：的

{
  "html_attributions" : [],
  "result" : {
    "address_components" : [
      {
        "long_name" : "48",
        "short_name" : "48",
        "types" : [ "street_number" ]
      },
      {
        "long_name" : "Pirrama Road",
        "short_name" : "Pirrama Road",
        "types" : [ "route" ]
      },
      {
        "long_name" : "Pyrmont",
        "short_name" : "Pyrmont",
        "types" : [ "locality", "political" ]
      },
      {
        "long_name" : "NSW",
        "short_name" : "NSW",
        "types" : [ "administrative_area_level_1", "political" ]
      },
      {
        "long_name" : "AU",
        "short_name" : "AU",
        "types" : [ "country", "political" ]
      },
      {
        "long_name" : "2009",
        "short_name" : "2009",
        "types" : [ "postal_code" ]
      }
    ],
    "formatted_address" : "5/48 Pirrama Road, Pyrmont NSW, Australia",
    "formatted_phone_number" : "[phone]",
    "geometry" : {
      "location" : {
        "lat" : -33.8669710,
        "lng" : 151.1958750
      }
    },
    "icon" : "http://maps.gstatic.com/mapfiles/place_api/icons/generic_business-71.png",
    "id" : "4f89212bf76dde31f092cfc14d7506555d85b5c7",
    "international_phone_number" : "[phone]",
    "name" : "Google Sydney",
    "rating" : 4.60,
    "reference" : "CnRlAAAAAfV6JIqSzL8Cf4VnXn0EaI1d5k3IPhdkEonq0MxiUbQFFSVuptVbXbNH4mrevb0bc7G8yWqTUv76i4KTuO_Wf3OrRHjCJJwzQ0mNLjbYGSVqy2eqyrgOUkl6S_sJfTbHzWZYrfPy7KZaet0mM5S6thIQJYuy5v_JD--ZxXEJLWTQRRoU5UaciXBBo89K-bce18Ii9RsEIws",
    "types" : [ "store", "establishment" ],
    "url" : "http://maps.google.com/maps/place?cid=10281119596374313554",
    "vicinity" : "5/48 Pirrama Road, Pyrmont",
    "website" : "http://www.google.com.au/"
  },
  "status" : "OK"
}

我们可以看到，坐标           位置 ： {             纬度：-33.8669710，             液化天然气：151.1958750           }

We can see that the coordinates are "location" : { "lat" : -33.8669710, "lng" : 151.1958750 }

然后，我们可以将请求发送到Panoramio的，插入的坐标，加在任一侧稍微回旋余地（我确实+/- 0.002度，形状200米×200米平方在赤道，通常更小）。 <$c$c>http://www.panoramio.com/map/get_panoramas.php?set=public&from=0&to=20&minx=-33.868&miny=151.193&maxx=-33.864&maxy=151.197&size=medium&mapfilter=true

Then we can send a request to Panoramio, inserting the coordinates, plus a little wiggle room on either side (I did +/- 0.002 degrees, a shape 200 m x 200 m square at the equator, generally smaller). http://www.panoramio.com/map/get_panoramas.php?set=public&from=0&to=20&minx=-33.868&miny=151.193&maxx=-33.864&maxy=151.197&size=medium&mapfilter=true

您可能需要做响应的一些过滤得到最接近的照片，但是这应该给你一些帮助。

You may need to do some filtering of the responses to get the closest photo, but this should give you something to work with.

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