如何替换多个匹配的正则表达式 [英] how to replace multiple matched Regex

问题描述

我有一组需要应用于一组String的正则表达式替换，

I have a set of regex replacements that are needed to be applied to a set of String,

例如：

1. 单个空格的所有多个空格（\\\ {2，} - >）


2. 全部。然后是一个char。其次是空格，后跟字符（\。（[a-zA-Z] - >。$ 1）

1. all multiple spaces with single space ("\s{2,}" --> " ")
2. all . followed by a char with . followed by space followed by the char (\.([a-zA-Z]-->". $1")

所以我会这样：

String s="hello     .how are you?";
s=s.replaceAll("\\s{2,}"," ");
s=s.replaceAll("\\.([a-zA-Z])",". $1");
....

它有效，但想象一下，我试图在长字符串上替换100多个这样的表达式。不用说这有多慢。

it works , however imagine I'm trying to replace 100+ such expressions on a long String. needless to say how slow this can be.

所以我的问题是如果有一种更有效的方法来使用单个replaceAll（或类似的东西，例如Pattern / Matcher）来推广这些替换

so my question is if there is a more efficient way to generalize these replacements with a single replaceAll (or something similar e.g. Pattern/Matcher)

我已经跟随Java替换多个不同的...... ，

但问题是我的正则表达式不是简单的字符串。

but the problem is that my regex(s) are not simple Strings.

推荐答案

你有这2个 replaceAll 来电：

s = s.replaceAll("\\s{2,}"," ");
s = s.replaceAll("\\.([a-zA-Z])",". $1");

您可以将它们合并为一个 replaceAll 像这样：

You can combine them into a single replaceAll like this:

s = s.replaceAll("\\s{2,}|(\\.)(?=[a-zA-Z])", "$1 ");

RegEx演示

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