如何从Java中的randDouble获得1到100之间的随机值？ [英] How to get a random between 1 - 100 from randDouble in Java?

问题描述

好的，我还是Java的新手。我们已经获得了一个帮助来创建一个游戏，您必须猜测计算机生成的随机整数。问题是我们的讲师坚持要求我们使用：

Okay, I'm still fairly new to Java. We've been given an assisgnment to create a game where you have to guess a random integer that the computer had generated. The problem is that our lecturer is insisting that we use:

double randNumber = Math.random();

然后将其转换为接受1 - 100（包括1和100）的随机整数。我有点不知所措。到目前为止我所拥有的是：

And then translate that into an random integer that accepts 1 - 100 inclusive. I'm a bit at a loss. What I have so far is this:

//Create random number 0 - 99
double randNumber = Math.random();
d = randNumber * 100;

//Type cast double to int
int randomInt = (int)d;

然而，随机双重延迟问题的随机性是0是可能的，而100不是。我想改变它，以便0不是可能的答案，100是。救命？

However, the random the lingering problem of the random double is that 0 is a possibility while 100 is not. I want to alter that so that 0 is not a possible answer and 100 is. Help?

推荐答案

你快到了。只需在结果中加1：

You're almost there. Just add 1 to the result:

int randomInt = (int)d + 1;

这会将你的范围转移到 1 - 100 而不是 0 - 99 。

This will "shift" your range to 1 - 100 instead of 0 - 99.

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