Java Transformer错误:无法编译样式表 [英] Java Transformer error: Could not compile stylesheet
问题描述
我想用Java中的XSLT转换XML。为此,我使用 javax.xml.transform
包。但是,我得到异常 javax.xml.transform.TransformerConfigurationException:无法编译样式表
。这是我正在使用的代码:
I'm want to transform a XML with XSLT in Java. For that I'm using the javax.xml.transform
package. However, I get the exception javax.xml.transform.TransformerConfigurationException: Could not compile stylesheet
. This is the code I'm using:
public static String transform(String XML, String XSLTRule) throws TransformerException {
Source xmlInput = new StreamSource(XML);
Source xslInput = new StreamSource(XSLTRule);
TransformerFactory tFactory = TransformerFactory.newInstance();
Transformer transformer = tFactory.newTransformer(xslInput); // this is the line that throws the exception
Result result = new StreamResult();
transformer.transform(xmlInput, result);
return result.toString();
}
请注意,我标记了抛出异常的行。
Note that I marked the line which throws the exception.
当我输入方法时, XSLTRule
的值为:
When I enter the method, the value of XSLTRule
is this:
<xsl:stylesheet version='1.0'
xmlns:xsl='http://www.w3.org/1999/XSL/Transform'
xmlns:msxsl='urn:schemas-microsoft-com:xslt'
exclude-result-prefixes='msxsl'
xmlns:ns='http://www.ibm.com/wsla'>
<xsl:strip-space elements='*'/>
<xsl:output method='xml' indent='yes'/>
<xsl:template match='@* | node()'>
<xsl:copy>
<xsl:apply-templates select='@* | node()'/>
</xsl:copy>
</xsl:template>
<xsl:template match="/ns:SLA
/ns:ServiceDefinition
/ns:WSDLSOAPOperation
/ns:SLAParameter[@name='Performance']"/>
</xsl:stylesheet>
推荐答案
public StreamSource(String systemId)
从URL构造StreamSource。我认为你正在传递XSLT的内容。试试这个:
Construct a StreamSource from a URL. I think you're passing the content of the XSLT instead. Try this:
File xslFile = new File("path/to/your/xslt");
TransformerFactory factory = TransformerFactory.newInstance();
Templates xsl = factory.newTemplates(new StreamSource(xslFile));
你还必须设置 OutputStream
你的 StreamResult
将写入:
You must also set the OutputStream
that your StreamResult
will write to:
ByteArrayOutputStream baos = new ByteArrayOutputStream();
Result result = new StreamResult(baos);
transformer.transform(xmlInput, result);
return baos.toString();
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