java.sql.SQLException:没有选择数据库 - 为什么? [英] java.sql.SQLException: No database selected - why?
问题描述
我试图学习如何通过Java访问mySQL数据库的最后几天。
我能够加载驱动程序并获得与数据库的连接(至少我是这么认为的,因为我没有在那里得到例外......)
the last days I was trying to learn how to access mySQL databases via Java.
I am able to load the driver and get a connection to the database ( at least I think so, since I don't get an exception there..)
代码是:
import java.sql.*;
public class test
{
public static void main(String[] args)
{
try
{
Class.forName("sun.jdbc.odbc.JdbcOdbcDriver");
System.out.println("driver loaded...");
}
catch(ClassNotFoundException e){
System.out.println("Error in loading the driver..."+e);
System.exit(0);
}
try
{
Connection dbConnection= DriverManager.getConnection("jdbc:odbc:test","root","password");
System.out.println("Connection successful...");
Statement stmt = dbConntection.createStatement();
stmt.executeUpdate("create table Accounts ( name char(20) )");
}
catch(SQLException e)
{
System.out.println("database-ConnectionError: "+e);
System.exit(0);
}
}
}
当我执行它时,它说:
驱动加载...
连接成功...
database-ConnectionError:java。 sql.SQLException:[MySQL] [ODBC 5.2(w)驱动程序] [mysqld-5.5.31]没有选择数据库
driver loaded...
Connection successful...
database-ConnectionError: java.sql.SQLException: [MySQL][ODBC 5.2(w) Driver][mysqld-5.5.31]No database selected
我真的不知道这个问题,因为我认为在getConnection过程中选择了数据库....
我试图通过添加这一行来选择数据库:
I really don't know the problem, because I thought the database is selected during the "getConnection" process....
I tried to select a database by adding this line:
stmt.executeUpdate("use test;");
。
不幸的是它没有用,因为我有另一个例外,它说我应该检查语法。我不明白,因为在我的命令行中它工作正常...
我不知道是否可以通过Java使用这些类型的命令,所以如果不是,请原谅我的错误。
unfortunately it didn't work because I got another exception which said I should check on the syntax. I don't understand that either because in my commandline it works just fine... I don't know if it is possible to use these type of commands via Java so if it isn't, please forgive my mistake.
我希望你能帮助我,我在搜索过程中没有错过这个解决方案!
I hope you can help me and I didn't miss the solution during my own search!
感谢所有回复并利用他们的时间处理我的问题的人!
Already Thanks to all who reply and use their time on my problems!
ps。如果我忘了指出一些重要的信息(我不认为我这样做)请问:)
ps. If I forgot to point out some important infos ( I don't think i did) please ask:)
编辑:我还试图在运行时创建一个新数据库
edit: I also tried to create a new database during runtime
stmt.executeUpdate("CREATE DATABASE test;");
这实际上有效,但数据库也不会被选中......
this actually works, but the database won't be selected either...
推荐答案
首先,我正在考虑我的答案,向您展示与MySQL数据库连接的另一种更好的方法,它更容易,更少nu-expected 例外。
你需要做一些步骤:
Firstly, I am considering my answer to show you another better way for connection with MySQL Database, it's much easier and less nu-expected Exception(s).
You need to do some steps:
- 下载 Connector / J 并将其添加到类路径中(如果您使用的是IDE,则添加
.jar
到图书馆,或者有很多关于 YouTube )。 - 在MySQL程序中创建数据库。
-
请参阅下面的示例为您演示如何在MySQL上连接和执行查询:
- Download Connector/J and add it to your class path(if you are using an IDE there is add the
.jar
to the library, or there is many tuts on YouTube). - Create your database in your MySQL program.
See this example below example below I made for you demonstrates how to connect and execute queries on MySQL :
import java.sql.*;
public class MySqlConnection {
private String MYSQL_DRIVER = "com.mysql.jdbc.Driver";
private String MYSQL_URL = "jdbc:mysql://localhost:3306/test";
private Connection con;
private Statement st;
private ResultSet rs;
public MySqlConnection() {
try {
Class.forName(MYSQL_DRIVER);
System.out.println("Class Loaded....");
con = DriverManager.getConnection(MYSQL_URL,"","");
System.out.println("Connected to the database....");
st = con.createStatement();
int c =st.executeUpdate("CREATE TABLE Accounts (Name VARCHAR(30))");
System.out.println("Table have been created.");
System.out.println(c+" Row(s) have been affected");
con.close();
} catch(ClassNotFoundException ex) {
System.out.println("ClassNotFoundException:\n"+ex.toString());
ex.printStackTrace();
} catch(SQLException ex) {
System.out.println("SQLException:\n"+ex.toString());
ex.printStackTrace();
}
}
public static void main(String...args) {
new MySqlConnection();
}
}
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