将字符串分解为大写的字符 [英] Breaking Strings into chars that are in upper case

问题描述

我正在制作一个方法来读取整个类代码并用它做一些事情。

I'm making a method to read a whole class code and do some stuff with it.

我想要做的是获取方法的名称，用它做一个字符串。

What I want to do is get the name of the method, and make a String with it.

类似removeProduct

Something like removeProduct

我将制作一个字符串删除产品

如何在大写情况下拆分名称方法？
如何构建这个新字符串，每个单词的第一个字母作为大写字母？
我正在使用子字符串，有没有更容易和更好的方法呢？

How can I split the name method in capital cases? How can I build this new string with the first letter of each word as capital case? I'm doing it with substring, is there a easier and better way to do it?

ps：我确定我的巴西英语没有标题帮助。如果有人能让它看起来更好，我会很感激。

ps: I'm sure my brazilian English didn't help on title. If anyone can make it looks better, I'd appreciate.

推荐答案

您可以使用正则表达式将名称拆分为各种单词，然后大写第一个：

You can use a regular expression to split the name into the various words, and then capitalize the first one:

public static void main(String[] args) {
    String input = "removeProduct";

    //split into words
    String[] words = input.split("(?=[A-Z])");

    words[0] = capitalizeFirstLetter(words[0]);

    //join
    StringBuilder builder = new StringBuilder();
    for ( String s : words ) {
        builder.append(s).append(" ");
    }

    System.out.println(builder.toString());

}

private static String capitalizeFirstLetter(String in) {
    return in.substring(0, 1).toUpperCase() + in.substring(1);
}

请注意，这需要更好的角落案件处理，例如不要在结束并处理1个字符。

Note that this needs better corner case handling, such as not appending a space at the end and handling 1-char words.

编辑：我的意思是解释正则表达式。正则表达式（？= [AZ]）是零宽度断言（正向前瞻）匹配下一个字符位于A和Z之间的位置。

Edit: I meant to explain the regex. The regular expression (?=[A-Z]) is a zero-width assertion (positive lookahead) matching a position where the next character is between 'A' and 'Z'.

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