使用正则表达式检查字符串至少有两个数字 [英] Using regex to check is string has at least two numbers

问题描述

在挖掘堆栈溢出后，我发现了一些代码，用于检查字符串是否为字母数字，且长度为8个字符。它很棒。现在，如果它包含至少2个数字，我该如何使它返回true？我想我必须在某处添加 \d {2} 。

After digging around on stack overflow, I found some code which checks if the string is alphanumeric and longer that 8 chars. It works great. Now how do I make it return true if it contains at least 2 numbers? I think I have to add \d{2} somewhere.

String pattern = "^[a-zA-Z0-9]*$";

if (s.matches(pattern) && s.length() >= 8){
    return true;
}
return false;

推荐答案

您不需要单独的if条件。单个正则表达式将为您完成所有操作。

You don't need a separate if condition. A single regex will do all for you.

String pattern = "^(?=.*?\\d.*\\d)[a-zA-Z0-9]{8,}$";

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