Java - 正则表达式问题 [英] Java - Regex problem

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问题描述

我有一个类型为


  • http://www.example.com/pk / ca

  • http://www.example.com/pk

  • http://www.example.com/anthingcangoeshere/pk

  • http://www.example.com/pkisnotnecessaryhere

  • http://www.example.com/pk/ca,
  • http://www.example.com/pk,
  • http://www.example.com/anthingcangoeshere/pk, and
  • http://www.example.com/pkisnotnecessaryhere.

现在,我想找到只有那些以 / pk / pk / 结尾的网址,并且<$ c之间没有任何内容$ c> .com 和 / pk

Now, I want to find out only those URLs that ends with /pk or /pk/ and don't have anything in between .com and /pk

推荐答案

直接翻译您的请求[...]以/ pk或/ pk /结尾且在.com和/ pk之间没有任何内容的网址,并额外假设应始终存在。 com,产生这个正则表达式:

Directly translating your request "[...] URLs that ends with /pk or /pk/ and don't have anything in between .com and /pk", with the additional assumption that there shall always be a ".com", yields this regex:

如果你使用 find()

\.com/pk/?$

如果您使用 matches()

.*\.com/pk/?

此处给出的其他答案给出了更多限制性模式,只允许更接近您的示例的网址。特别是我的模式不验证给定的字符串是语法上有效的URL。

Other answers given here give more restrictive patterns, allowing only URLs that are more close to your examples. Especially my pattern does not validate that the given string is a syntactically valid URL.

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