将零添加到单个数字，是否可能？ [英] Adding zero to a single digit number, Is it possible?
问题描述
public class MultiplicationTable {
public static void main (String[]a){
int[] x;
x = new int[10];
int i;
int n=0;
for (i=0;i<x.length;i++){
n++;
x[i]=n;
System.out.print(x[i] + " ");
}
System.out.println();
for (i=0;i<x.length;i++)
System.out.print(x[0] * x[i] + " ");
System.out.println();
for (i=0;i<x.length;i++)
System.out.print(x[1] * x[i] + " ");
System.out.println();
for (i=0;i<x.length;i++)
System.out.print(x[2] * x[i] + " ");
System.out.println();
for (i=0;i<x.length;i++)
System.out.print(x[3] * x[i] + " ");
System.out.println();
for (i=0;i<x.length;i++)
System.out.print(x[4] * x[i] + " ");
System.out.println();
for (i=0;i<x.length;i++)
System.out.print(x[5] * x[i] + " ");
System.out.println();
for (i=0;i<x.length;i++)
System.out.print(x[6] * x[i] + " ");
System.out.println();
for (i=0;i<x.length;i++)
System.out.print(x[7] * x[i] + " ");
System.out.println();
for (i=0;i<x.length;i++)
System.out.print(x[8] * x[i] + " ");
System.out.println();
for (i=0;i<x.length;i++)
System.out.print(x[9] * x[i] + " ");
}
}
这是一个将显示如下乘法表的程序：
This is a program that will display a Multiplication Table like this:
1 2 3 4 5 6 7 8 9 10
1 2 3 4 5 6 7 8 9 10
1 2 3 4 5 6 7 8 9 10
1 2 3 4 5 6 7 8 9 10
2 4 6 8 10 12 14 16 18 20
2 4 6 8 10 12 14 16 18 20
3 6 9 12 15 18 21 24 27 30
3 6 9 12 15 18 21 24 27 30
4 8 12 16 20 24 28 32 36 40
4 8 12 16 20 24 28 32 36 40
5 10 15 20 25 30 35 40 45 50
5 10 15 20 25 30 35 40 45 50
6 12 18 24 30 36 42 48 54 60
6 12 18 24 30 36 42 48 54 60
7 14 21 28 35 42 49 56 63 70
7 14 21 28 35 42 49 56 63 70
8 16 24 32 40 48 56 64 72 80
8 16 24 32 40 48 56 64 72 80
9 18 27 36 45 54 63 72 81 90
9 18 27 36 45 54 63 72 81 90
10 20 30 40 50 60 70 80 90 100
10 20 30 40 50 60 70 80 90 100
================================================== =============
===============================================================
它正在运行且正确，但我希望它看起来像这样：
It is running and correct but I want it to look like this one:
01 02 03 04 05 06 07 08 09 10
01 02 03 04 05 06 07 08 09 10
01 02 03 04 05 06 07 08 09 10
01 02 03 04 05 06 07 08 09 10
02 04 06 08 10 12 14 16 18 20
02 04 06 08 10 12 14 16 18 20
03 06 09 12 15 18 21 24 27 30
03 06 09 12 15 18 21 24 27 30
04 08 12 16 20 24 28 32 36 40
04 08 12 16 20 24 28 32 36 40
05 10 15 20 25 30 35 40 45 50
05 10 15 20 25 30 35 40 45 50
06 12 18 24 30 36 42 48 54 60
06 12 18 24 30 36 42 48 54 60
07 14 21 28 35 42 49 56 63 70
07 14 21 28 35 42 49 56 63 70
08 16 24 32 40 48 56 64 72 80
08 16 24 32 40 48 56 64 72 80
09 18 27 36 45 54 63 72 81 90
09 18 27 36 45 54 63 72 81 90
10 20 30 40 50 60 70 80 90 100
10 20 30 40 50 60 70 80 90 100
============== =================================
===============================================
有吗无论如何？
推荐答案
是的，你可以！您可以使用 String.format 为输出添加零填充。
Yes you can! You can use String.format to add zero padding to your output.
示例：
String.format（％05d，2）将产生 00002 。
对当前代码的一些改进：
Some improvement on the current code:
我不确定你为什么打算将数字存储在里面一个数组（可能用于练习目的），但这并不是必要的，因为无论如何它都是从1到10。虽然如果你想这样做，你不需要 i 和 n 。
I'm not sure why you intend to store the numbers inside an array (for practice purpose maybe), but that is not necessary as it goes from 1 to 10 anyway. Though if you want to do that, you don't need both i and n.
for (i=0; i<x.length; i++){
x[i] = i+1;
System.out.print(x[i] + " ");
}
其次，我确定你意识到你有很多重复的代码，这是相当顺序的。你可以使用2个嵌套for循环，而不是10个单循环：
Secondly, I'm sure you realize that you have a lot of duplicate code, and it's quite sequential. You can do that using 2 nested for loops, instead of having 10 single loops:
for (int row = 1; row <= 10; row++) {
for (int col = 1; col <= 10; col++)
System.out.print(String.format("%03d", row * col));
System.out.println();
}
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