Java Alphabetizing Strings [英] Java Alphabetizing Strings
本文介绍了Java Alphabetizing Strings的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个课程项目,我需要输入4个不同的字符串,然后按字母顺序输出。
I have a project for class were I need to get 4 different strings inputted and then output them in alphabetical order.
到目前为止我有这个:
String wd1, wd2, wd3, wd4;
Scanner scan1 = new Scanner(System.in);
System.out.println ("Type Word One: ");
wd1 = scan1.next();
System.out.println ("Type Word Two: ");
wd2 = scan1.next();
System.out.println ("Type Word Three: ");
wd3 = scan1.next();
System.out.println ("Type Word Four: ");
wd4 = scan1.next();
我知道我可以通过以下方式获得2个字符串的字母顺序:
I know that I can get the alphabetical order of 2 strings by using:
int compare = wd1.compareTo(wd2);
if (compare < 0)
{System.out.println(wd1 + " " + wd2);}
else {
if (compare > 0)
{System.out.println(wd2+ " " + wd1);}
我需要帮助以正确的顺序获取所有4个字符串。 我应该使用if else语句而不是数组来执行此操作。
I need help getting all 4 of the strings in the proper order. I am supposed to be using if else statements and not arrays to do this.
任何帮助都会很棒!
谢谢
推荐答案
boolean swapped = false;
do {
swapped = false;
if (w2.compareTo(w1) < 0) {
String tmp = w2;
w2 = w1;
w1 = tmp;
swapped = true;
}
if (w3.compareTo(w2) < 0) {
String tmp = w3;
w3 = w2;
w2 = tmp;
swapped = true;
}
if (w4.compareTo(w3) < 0) {
String tmp = w4;
w4 = w3;
w3 = tmp;
swapped = true;
}
} while (swapped)
System.out.println(w1);
System.out.println(w2);
System.out.println(w3);
System.out.println(w4);
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