如何以正确的顺序迭代/浏览字符集中的每个字符（例如，US-ASCII或IBM037）？ [英] How to iterate/navigate through each character in a character set (e.g., US-ASCII or IBM037, in proper sequence)?

问题描述

我想迭代字符集中的每个字符（主要是US-ASCII和IBM037），然后以正确的字符集顺序打印所有字母数字字符（或所有可打印字符）。是否可以不创建静态数组？

I want to iterate through each character in a character set (primarily US-ASCII and IBM037) and then print all alphanumeric characters (or all printable characters) in the proper character set sequence. Is it possible without creating static arrays?

推荐答案

这对我有用。感谢所有的反馈！

This worked for me. Thanks for all the feedback!

final Charset charset = Charset.forName(charsetName);
for (int i = 0; i < 255; i++) {
    ByteBuffer bb = ByteBuffer.allocate(4);
    bb.putInt(i);
    System.out.println(new String(bb.array(), charset).trim());
}

这篇关于如何以正确的顺序迭代/浏览字符集中的每个字符（例如，US-ASCII或IBM037）？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！