解析长到负数 [英] parse long to negative number

问题描述

代码：

public class Main{
    public static void main(String[] a){
        long t=24*1000*3600;
        System.out.println(t*25);
        System.out.println(24*1000*3600*25);
    }
}

打印：

2160000000

-2134967296

为什么？

感谢所有回复。

这是在数字后使用L的唯一方法吗？

Is the only way to use L after the number?

我试过（长）24 * 1000 * 3600 * 25 但这也是否定的。

I have tried the (long)24*1000*3600*25 but this is also negative.

推荐答案

要清楚解释，

System.out.println(24*1000*3600*25);

在上面的语句中实际上是 int literals 。要将它们视为 long 字面值，您需要为 L 后缀。

In the above statement are actually int literals. To make treat them as a long literal you need to suffix those with L.

System.out.println(24L*1000L*3600L*25L);

警告，一个小的 l 也足够了，但有时看起来像大写我或 1 。资本我在这里没有多大意义，但读到 1 确实会给你带来困难。此外，即使用 L 填充单个值，结果 long 。

Caveat, a small l will suffice too, but that looks like capital I or 1, sometimes. Capital I doesn't make much sense here, but reading that as 1 can really give hard time. Furthermore, Even sufficing a single value with L will make the result long.

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