java @Asynchronous方法:不运行异步 [英] java @Asynchronous Methods: not running async
问题描述
我尝试让异步进程运行。
基于此示例: http://tomee.apache。 org / examples-trunk / async-methods / README.html
I try to get an async process running. Based on this example: http://tomee.apache.org/examples-trunk/async-methods/README.html
但方法 addWorkflow(工作流工作流程)
仅在运行(工作流工作流程)
中的代码完全完成时返回。
But the method addWorkflow(Workflow workflow)
will only return when the code in run(Workflow workflow)
is fully completed.
然后当它返回并且 result.get();
被调用我将获得异常:
Then when it returns and result.get();
is called I'll get the exception:
引起:java.lang.IllegalStateException:对象不表示真正的未来
Caused by: java.lang.IllegalStateException: Object does not represent an acutal Future
有什么建议我缺少什么?
Any suggestion what I'm missing?
@Singleton
public class WorkflowProcessor {
@EJB
private WorkflowManager workflowManager;
private final static Logger log = Logger.getLogger(WorkflowProcessor.class.getName());
public void runWorkflows(Collection<Workflow> workflows) throws Exception{
final long start = System.nanoTime();
final long numberOfWorkflows = workflows.size();
Collection<Future<Workflow>> asyncWorkflows = new ArrayList<>();
for(Workflow workflow : workflows){
Future<Workflow> w = addWorkflow(workflow);
asyncWorkflows.add(w);
}
log.log(Level.INFO, "workflow jobs added {0}", new Object[]{numberOfWorkflows});
for(Future<Workflow> result : asyncWorkflows){
result.get();
}
final long total = TimeUnit.NANOSECONDS.toSeconds(System.nanoTime() - start);
log.log(Level.INFO, "WorkflowProcessor->runWorkflows {0} workflows completed in:{1}", new Object[]{numberOfWorkflows, total});
}
@Asynchronous
@Lock(LockType.READ)
@AccessTimeout(-1)
private Future<Workflow> addWorkflow(Workflow workflow){
run(workflow);
return new AsyncResult<Workflow>(workflow);
}
private void run(Workflow workflow){
this.workflowManager.runWorkflow(workflow);
}
推荐答案
问题在于Java可以不要修饰隐含的this指针。
The issue is that Java can't decorate the implicit this pointer.
换句话说,@ Asynchronous注释将不会被处理,你正在进行普通的方法调用。
In other words, the @Asynchronous annotation won't be processed and you're doing an ordinary method call.
你可以注入你的单身人士,引用自己(称之为自我),然后调用self.addWorkflow。
You can inject your so singleton with a reference to itself (call this e.g. "self"), then call self.addWorkflow.
您可能还想考虑在无状态bean中运行异步代码。您正在为addWorkflow使用读锁定,但runWorkflow仍然具有写锁定。我认为你现在有一个死锁:你持有锁直到工作完成,但是在写锁被释放之前无法完成任务。
You might also want to consider running your async code in a stateless bean. You are using a read lock for addWorkflow, but runWorkflow still has a write lock. I think you have a dead lock now: you're holding the lock until work is done, but no work can be done until the write lock is released.
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