基于逗号分裂忽略逗号内部逗号的正则表达式 [英] Regular Expression for Comma Based Splitting Ignoring Commas inside Quotes

问题描述

在我的一个项目中，我不得不处理逗号分隔文件（CSV）。我不得不根据逗号拆分数据，忽略引号内的逗号（即）所以我使用了一个提到的表达式另一个堆栈溢出问题（ Java：拆分逗号分隔的字符串，但忽略引号中的逗号）。一切都工作正常，直到最近我注意到它不适用于下面提到的一个特定场景。

In one of my projects I had to deal with Comma Separated files (CSV). I had to split data based on Comma , ignoring commas inside quotes (i.e. "") so I used an expression mentioned on another stack overflow question (Java: splitting a comma-separated string but ignoring commas in quotes). Everything was working fine until recently I noticed that it is not working for one specific scenario mentioned below.

我有一个数据字符串需要在Commas上分割为：

I have a data string needed to split on Commas as:

20Y-62-27412,20Y6227412NK,BRACKET,101H,00D505060,H664374,06/25/2013,1,,

根据我的理解基于表达式

In my understanding based on expression

String[] rowData = str.split(",(?=([^\"]*\"[^\"]*\")*[^\"]*$)");

分割后的数据应该返回一个大小为10的数组，其中包含最后两个数组索引包含一个空字符串，而不是我得到一个大小为8的数组，最后两个逗号不被视为拆分器。我在我的应用程序的几个地方使用了这个表达式，所以我不想从这里回溯。任何帮助将不胜感激谢谢

Data after splitting should return me an array of size 10 with last two indexes of array containing an empty string, Instead I am getting an array of size 8 being last two commas not treated as splitter. I have used this expression on several places in my application so I don't want to backtrack from this. Any help would be appreciated. Thanks

推荐答案

你需要使用 split（java.lang.String，int）
method

You need to use the split(java.lang.String, int) method

您的代码将如下所示：

String str = "20Y-62-27412,20Y6227412NK,BRACKET,101H,00D505060,H664374,06/25/2013,1,,";
String[] rowData = str.split(",(?=([^\"]*\"[^\"]*\")*[^\"]*$)", -1);

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