Android的web视图与后退按钮，如果其他人 [英] Android Webview with Back Button, if else

问题描述

否认。我打开安装了错误的应用程序。它奇妙的作品。 ：）

我有后退按钮正常工作我的web视图中，但我想知道的东西。 如何使web视图回去，直到它再也看不到，而不是退出程序，把它打开了一个对话框，询问用户是否确保他们不会退出。 这里是我的作为在code。
感谢您抽出宝贵的时间。

.java文件

 包com.vtd.whatthe;

进口android.app.Activity;
进口android.app.AlertDialog;
进口android.app.AlertDialog.Builder;
进口android.app.Dialog;
进口android.content.DialogInterface;
进口android.os.Bundle;
进口android.view.KeyEvent;
进口android.view.View;
进口android.widget.Toast;
进口android.webkit.WebView;
进口android.webkit.WebViewClient;

公共类WhatThe延伸活动{
    私人的WebView的WebView;

    / **第一次创建活动时调用。 * /

    公共无效onBack pressed（）{

        如果（webview.isFocused（）＆安培;＆安培; webview.canGoBack（））{
                webview.goBack（）;
        }
        其他 {
                openMyDialog（空）;

        }
    }

    @覆盖
    公共无效的onCreate（包savedInstanceState）{
        super.onCreate（savedInstanceState）;
        的setContentView（R.layout.main）;
        的WebView =（web视图）findViewById（R.id.webview）;
        webview.setWebViewClient（新HelloWebViewClient（））;
        webview.getSettings（）setJavaScriptEnabled（真）。
        webview.setInitialScale（50）;
        。webview.getSettings（）setUseWideViewPort（真正的）;
        webview.loadUrl（http://test2.com/）;
    }
    私有类HelloWebViewClient扩展WebViewClient {

        公共布尔shouldOverrideUrlLoading（web视图查看，字符串URL）{
            view.loadUrl（URL）;
            返回true;
        }

            }

    公共无效openMyDialog（查看视图）{
        的ShowDialog（10）;
    }

    @覆盖
    受保护的对话框onCreateDialog（INT ID）{
        开关（ID）{
        案例10：
            //创建我们的AlertDialog
            建设者建设者=新AlertDialog.Builder（本）;
            builder.setMessage（你确定要退出吗？你有无限的猜测！）
                    .setCancelable（真）
                    .setPositiveButton（是，
                            新DialogInterface.OnClickListener（）{
                                @覆盖
                                公共无效的onClick（DialogInterface对话框，
                                        其中INT）{
                                    //结束活动
                                    WhatThe.this.finish（）;
                                }
                            }）
                    .setNegativeButton（继续猜！，
                            新DialogInterface.OnClickListener（）{

                                @覆盖
                                公共无效的onClick（DialogInterface对话框，
                                        其中INT）{
                                    Toast.makeText（getApplicationContext（），
                                            祝你好运！，
                                            Toast.LENGTH_SHORT）.show（）;
                                }
                            }）;

            返回builder.create（）;


        }
        返回super.onCreateDialog（ID）;
    }
}
 

解决方案

以下code为我工作。

 公共无效onBack pressed（）{

    如果（webview.isFocused（）＆安培;＆安培; webview.canGoBack（））{
            webview.goBack（）;
    }
    其他 {
            super.onBack pressed（）;
            完（）;
    }
}
 

Disregard. I was opening the wrong app that was installed. It works wonderfully. :)

I have the back button working correctly within my webview, but I was wondering something. How to make the webview go back until it cannot anymore, and instead of exiting the program, have it open up a dialog box asking if the user is sure they won't to exit. Here is my take on the code.
Thanks for taking the time.

.java file

package com.vtd.whatthe;

import android.app.Activity;
import android.app.AlertDialog;
import android.app.AlertDialog.Builder;
import android.app.Dialog;
import android.content.DialogInterface;
import android.os.Bundle;
import android.view.KeyEvent;
import android.view.View;
import android.widget.Toast;
import android.webkit.WebView;
import android.webkit.WebViewClient;

public class WhatThe extends Activity {
    private WebView webview;

    /** Called when the activity is first created. */

    public void onBackPressed (){

        if (webview.isFocused() && webview.canGoBack()) {
                webview.goBack();       
        }
        else {
                openMyDialog(null);

        }
    }

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        webview = (WebView) findViewById(R.id.webview);
        webview.setWebViewClient(new HelloWebViewClient());
        webview.getSettings().setJavaScriptEnabled(true);
        webview.setInitialScale(50); 
        webview.getSettings().setUseWideViewPort(true); 
        webview.loadUrl("http://test2.com/");
    }
    private class HelloWebViewClient extends WebViewClient {

        public boolean shouldOverrideUrlLoading(WebView view, String url) {
            view.loadUrl(url);
            return true;
        }

            }

    public void openMyDialog(View view) {
        showDialog(10);
    }

    @Override
    protected Dialog onCreateDialog(int id) {
        switch (id) {
        case 10:
            // Create our AlertDialog
            Builder builder = new AlertDialog.Builder(this);
            builder.setMessage("Are you sure you want to exit? You have unlimited guesses!")
                    .setCancelable(true)
                    .setPositiveButton("Yes",
                            new DialogInterface.OnClickListener() {
                                @Override
                                public void onClick(DialogInterface dialog,
                                        int which) {
                                    // Ends the activity
                                    WhatThe.this.finish();
                                }
                            })
                    .setNegativeButton("Keep Guessing!",
                            new DialogInterface.OnClickListener() {

                                @Override
                                public void onClick(DialogInterface dialog,
                                        int which) {
                                    Toast.makeText(getApplicationContext(),
                                            "Good Luck!",
                                            Toast.LENGTH_SHORT).show();
                                }
                            });

            return builder.create();


        }
        return super.onCreateDialog(id);
    }
}

解决方案

The below code worked for me

public void onBackPressed (){

    if (webview.isFocused() && webview.canGoBack()) {
            webview.goBack();       
    }
    else {
            super.onBackPressed();
            finish();
    }
}

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