想要在String中搜索，如果有任何特殊字符 [英] Want to search in String if there is any special characters in it

问题描述

我想搜索java字符串中的任何特殊字符。
这里是我的代码

I want to search any special char in java string. here is my code

    Pattern p = Pattern.compile("^[a-zA-Z0-9 ]");
    Matcher m = p.matcher("hgbs!hf862376");
    boolean b = m.matches();

    if (b == true)
       System.out.println("sp. character is there");

但这不起作用。
任何人都可以为此建议正确的正则表达式。
我想只允许az，AZ和0-1。

But this is not working. Can any one suggest correct Regex for this. I want to allowed only a-z,A-Z and 0-1.

提前谢谢你。

推荐答案

。* [^ a-zA-Z0-9]。* 而不是 ^ [a -zA-Z0-9]

^字符类（即方括号）表示否定，所以除了列出的字符外。如果不在字符类中，则^表示字符串的开始。
您还需要在特殊字符之前或之后匹配任何内容。
因此，您的原始正则表达式只匹配 a-zA-Z0-9 中包含单个字母的字符串。

^ within character class (i.e. square brackets) mean negation, so any but the characters listed. If not within character class, ^ means the beggining of the string. Also you need to match anything before or after the special character. So your original regex would have matched only strings that have a single letter among a-zA-Z0-9.

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