基于用户输入在Java中打印钻石形状 [英] Printing A Diamond Shape In Java, Based On User Input
问题描述
我正在尝试编写的程序出现问题。用户输入正奇数,否则程序会提示用户,直到他们这样做。当它们执行时,程序打印对应于用户输入的菱形。
I have a problem with a program I am trying to write. A user inputs a positive odd integer, otherwise the program prompts the user until they do. When they do, the program prints a diamond shape corresponding to the user input.
到目前为止我有这件作品打印出这样一个人物的左手对角线,但无法弄清楚如何打印其余部分。以下是代码:
I have this piece so far that prints the left hand diagonal of such a figure, but cannot figure out how to print the rest of it. Here is the code:
import java.util.Scanner;
public class DrawingProgram {
public static void main(String[] args) {
Scanner keyboard = new Scanner(System.in);
System.out.println("Welcome to the drawing program:");
System.out.println("Please Input a Positive Odd Integer:");
char userAnswer;
int userInput;
userInput = keyboard.nextInt();
if (userInput%2 == 0){
System.out.println("That is not a Positive Odd Integer!");
}
else if (userInput < 0){
System.out.println("That is not a Positive Odd Integer");
}
else if (userInput%2 == 1){
for (int row = 1; row<= userInput; row++){
for (int col = 1; col<= userInput; col++ ){
if (row+col==userInput-1 )
System.out.print( "*");
else
System.out.print( " ");
}
System.out.print("\n");
}
}
}
}
推荐答案
用户输入一个正奇数,否则程序会提示
用户直到
A user inputs a positive odd integer, otherwise the program prompts the user until they do
你需要在循环中扫描
do
{
userInput = keyboard.nextInt();
if (userInput % 2 == 0)
System.out.println("That is not an Odd Integer!");
if(userInput < 0)
System.out.println("That is not a Positive Odd Integer");
} while(userInput < 0 || userInput %2 == 0);
现在你可以删除那个验证 else if(userInput%2 == 1 ){
Now you can remove that validation else if (userInput%2 == 1){
现在我在循环检查时发现的第一件事是 if(row + col == userInput -1 ||)
由于您没有跟随的比较运算符,因此无法编译。
Now the first thing I realize when checking at your loop is if (row+col==userInput-1 || )
which won't compile as you have a comparison operator with nothing following.
请注意,您可以替换 System.out.print(\ n);
带 System.out.println()
但这不是真的重要...
Note that you can replace System.out.print("\n");
with System.out.println("")
but that's not really important...
现在替换你的循环条件,使它们从0开始
Now replace your loop condition so that they start as 0
for (int row = 0; row <= userInput; row++){
for (int col = 0; col <= userInput; col++ ){
既然你想要一个钻石,你需要有4个对角线,所以有2个循环(一个用于顶部和底部)......
Now since you want a Diamond, you need to have 4 diagonal, so 2 loops (one for top and bottom)...
for (int i = 1; i < userInput; i += 2)//Draw the top of the diamond
{
for (int j = 0; j < userInput - 1 - i / 2; j++)//Output correct number of spaces before
{
System.out.print(" ");
}
for (int j = 0; j < i; j++)//Output correct number of asterix
{
System.out.print("*");
}
System.out.print("\n");//Skip to next line
}
for (int i = userInput; i > 0; i -= 2)//Draw the bottom of the diamond
{
for (int j = 0; j < userInput -1 - i / 2; j++)
{
System.out.print(" ");
}
for (int j = 0; j < i; j++)
{
System.out.print("*");
}
System.out.print("\n");
}
所以最终代码看起来像这样
So the final code would look like this
public static void main(String[] args)
{
Scanner keyboard = new Scanner(System.in);
System.out.println("Welcome to the drawing program:");
System.out.println("Please Input a Positive Odd Integer:");
char userAnswer;
int userInput;
do
{
userInput = keyboard.nextInt();
if (userInput % 2 == 0)
{
System.out.println("That is not an Odd Integer!");
}
if (userInput < 0)
{
System.out.println("That is not a Positive Odd Integer");
}
} while (userInput < 0 || userInput % 2 == 0);
for (int i = 1; i < userInput; i += 2) //This is the number of iterations needed to print the top of diamond (from 1 to userInput by step of two for example with 5 = {1, 3, 5} so 3 rows.
{
for (int j = 0; j < userInput - 1 - i / 2; j++)//write correct number of spaces before, example with 5 = j < 5 - 1 -i / 2, so it would first print 4 spaces before, with 1 less untill it reach 0
{
System.out.print(" ");//write a space
}
for (int j = 0; j < i; j++)
{
System.out.print("*");//write an asterix
}
System.out.println("");
}
// Same logic apply here but backward as it is bottom of diamond
for (int i = userInput; i > 0; i -= 2)
{
for (int j = 0; j < userInput -1 - i / 2; j++)
{
System.out.print(" ");
}
for (int j = 0; j < i; j++)
{
System.out.print("*");
}
System.out.print("\n");
}
}
这篇关于基于用户输入在Java中打印钻石形状的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!