Java和C＃中的volatile语义背后的原因是什么？ [英] what is the reasoning behind volatile semantics in Java and C#

问题描述

C＃和Java都定义了

* volatile读取具有获取语义

* volatile写入具有发布语义




我的问题是：

1. 这是定义volatile的唯一正确方法。


2. 如果没有，如果语义被颠倒，那么事情就会大不相同，那就是
   
   
   
   
   • volatile读取具有释放语义
   
   
   • volatile写入具有获取语义
   
   

解决方案

volatile背后的原因语义植根于

Both C# and Java define that
* volatile reads have acquire semantics
* volatile writes have release semantics

My questions are:

1. Is this the only correct way to define volatile.
2. If not, will things be awfully different if the semantics were reversed, that is
   
   • volatile reads have release semantics
   • volatile writes have acquire semantics

解决方案

The reasoning behind the volatile semantic is rooted in the Java Memory Model, which is specified in terms of actions:

• reads and writes to variables
• locks and unlocks of monitors
• starting and joining with threads

The Java Memory Model defines a partial ordering called happens-before for the actions which can occur in a Java program. Normally there is no guarantee, that threads can see the results of each other actions.

Let's say you have two actions A and B. In order to guarantee, that a thread executing action B can see the results of action A, there must be a happens-before relationship between A and B. If not, the JVM is free to reorder them as it likes.

A program which is not correctly synchronized might have data races. A data race occurs, when a variable is read by > 1 threads and written by >= 1 thread(s), but the read and write actions are not ordered through the happens-before ordering.

Hence, a correctly synchronized program has no data races, and all actions within the program happen in a fixed order.

So actions are generally only partially ordered, but there is also a total order between:

• lock acquisition and release
• reads and writes to volatile variables

These actions are totally ordered.

This makes it sensible to describe happens-before in terms of "subsequent" lock acquisitions and reads of volatile variables.

Regarding your questions:

1. With the happen-before relationship you have an alternative definition of volatile
2. Reversing the order would not make sense to the definition above, especially since there is a total order involved.

This illustrates the happens-before relation when two threads synchronize using a common lock. All the actions within thread A are ordered by the program order rule, as are the actions within thread B. Because A releases lock M and B subsequently acquires M, all the actions in A before releasing the lock are therefore ordered before the actions in B after acquiring the lock. When two threads synchronize on different locks, we can't say anything about the ordering of actions between themthere is no happens-before relation between the actions in the two threads.

Source: Java Concurrency in Practice

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