找到从特殊字符java开始的单词 [英] Find the words start from a special character java
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问题描述
我想在java中的字符串中找到以#符号开头的单词。标志和单词之间也可以有空格。
I want to find the words that start with a "#" sign in a string in java. There can be spaces between the sign and the word as well.
字符串hi #how are#you
将输出为:
how
you
我用regex尝试了这个,但仍然找不到合适的模式。请帮帮我。
I have tried this with regex, but still could not find a suitable pattern. Please help me on this.
谢谢。
推荐答案
使用#\ * *(\ w +)
as你的正则表达式。
Use #\s*(\w+)
as your regex.
String yourString = "hi #how are # you";
Matcher matcher = Pattern.compile("#\\s*(\\w+)").matcher(yourString);
while (matcher.find()) {
System.out.println(matcher.group(1));
}
这将打印出来:
how
you
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