如何获得数组的最小值，最大值？ [英] how to get the minimum,maximum value of an array?

问题描述

这是我的代码。我需要得到我的数组的最小值，最大值，以便能够得到范围，每当我输入数字时，最小值为0.请帮助我。谢谢：）

Here's my code. I need to get the minimum,maximum value of my array to be able for me get the range, whenever I input numbers the minimum value is 0. Please help me. Thank you:)

final AutoCompleteTextView inputValues = (AutoCompleteTextView) findViewById(R.id.txt_input);
final TextView txtMinimum = (TextView) findViewById(R.id.txtMinimum);
final TextView txtMaximum = (TextView) findViewById(R.id.txtMaximum);
final TextView txtRange = (TextView) findViewById(R.id.txtRange);

Button btncalculate = (Button)findViewById(R.id.btncalculate);
btncalculate.setOnClickListener(new OnClickListener() {

    @Override
    public void onClick(View arg0) {
        String []values = ( inputValues.getText().toString().split(","));
        int[] convertedValues = new int[values.length];

        // calculate for the minimum and maximum number
        int min = 0;
        int max=0;

        min = max = convertedValues[0];
        for (int i = 0; i < convertedValues.length; ++i) {
            convertedValues[i] =Integer.parseInt(values[i]);
            min = Math.min(min, convertedValues[i]);
            max = Math.max(max, convertedValues[i]);
        }
        txtMinimum.setText(Integer.toString(min));
        txtMaximum.setText(Integer.toString(max));

        // calculate for the range
        int range=max - min;
        txtRange.setText(Integer.toString(range));

    }});

推荐答案

int[] convertedValues = new int[10];
int max = convertedValues[0];

for (int i = 1; i < convertedValues.length; i++) {
    if (convertedValues[i] > max) {
        max = convertedValues[i];
    }
}

同样通过更改较小的符号来查找最小值。

Similarly find for the minimum value by changing lesser symbol.

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