来自ZipInputStream的ZipEntry的getInputStream（不使用ZipFile类） [英] getInputStream for a ZipEntry from ZipInputStream (without using the ZipFile class)

问题描述

如何从 ZipInputStream ZipEntry 的 InputStream c $ c>不使用 ZipFile 类？

How can I get an InputStream for a ZipEntry from a ZipInputStream without using the ZipFile class?

推荐答案

它有效这样

static InputStream getInputStream(File zip, String entry) throws IOException {
    ZipInputStream zin = new ZipInputStream(new FileInputStream(zip));
    for (ZipEntry e; (e = zin.getNextEntry()) != null;) {
        if (e.getName().equals(entry)) {
            return zin;
        }
    }
    throw new EOFException("Cannot find " + entry);
}

public static void main(String[] args) throws Exception {
    InputStream in = getInputStream(new File("f:/1.zip"), "launch4j/LICENSE.txt");
    Scanner sc = new Scanner(in);
    while(sc.hasNextLine()) {
        System.out.println(sc.nextLine());
    }
    in.close();
}

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