在Spring MVC REST中返回文件 [英] Return file in Spring MVC REST

问题描述

我有REST服务代码下面的代码返回一个文件，现在问题是在PostMan客户端的响应主体中我得到一个原始响应，我怎么能转换它以便它显示文件的内容到客户端，目标是将文件返回给用户.File Name是File1.jpeg

I have the REST Service Code Below code which returns a File ,now the problem is in the response body on the PostMan Client I get a raw response ,how can I can convert it so that it displays the contents of the file to the client ,Goal is to return a file to the user .File Name is "File1.jpeg"

代码：

@RequestMapping(value = URIConstansts.GET_FILE, produces = { "application/json" }, method = RequestMethod.GET)
public @ResponseBody ResponseEntity getFile(@RequestParam(value="fileName", required=false) String fileName,HttpServletRequest request) throws IOException{

    ResponseEntity respEntity = null;

    byte[] reportBytes = null;
    File result=new File("/home/arpit/Documents/PCAP/dummyPath/"+fileName);

    if(result.exists()){
        InputStream inputStream = new FileInputStream("/home/arpit/Documents/PCAP/dummyPath/"+fileName); 


        byte[]out=org.apache.commons.io.IOUtils.toByteArray(inputStream);

        HttpHeaders responseHeaders = new HttpHeaders();
        responseHeaders.add("content-disposition", "attachment; filename=" + fileName);

        respEntity = new ResponseEntity(out, responseHeaders,HttpStatus.OK);


    }else{

        respEntity = new ResponseEntity ("File Not Found", HttpStatus.OK);
    }


    return respEntity;

}

推荐答案

代码下面解决了我的问题：

The code below solved my problem:

@RequestMapping(value = URIConstansts.GET_FILE, produces = { "application/json" }, method = RequestMethod.GET)
public @ResponseBody ResponseEntity getFile(@RequestParam(value="fileName", required=false) String fileName,HttpServletRequest request) throws IOException{

    ResponseEntity respEntity = null;

    byte[] reportBytes = null;
    File result=new File("/home/arpit/Documents/PCAP/dummyPath/"+fileName);

    if(result.exists()){
        InputStream inputStream = new FileInputStream("/home/arpit/Documents/PCAP/dummyPath/"+fileName);
        String type=result.toURL().openConnection().guessContentTypeFromName(fileName);

        byte[]out=org.apache.commons.io.IOUtils.toByteArray(inputStream);

        HttpHeaders responseHeaders = new HttpHeaders();
        responseHeaders.add("content-disposition", "attachment; filename=" + fileName);
        responseHeaders.add("Content-Type",type);

        respEntity = new ResponseEntity(out, responseHeaders,HttpStatus.OK);
    }else{
        respEntity = new ResponseEntity ("File Not Found", HttpStatus.OK);
    }
    return respEntity;
}

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