在线阅读XML并存储它(使用Java) [英] Reading XML online and Storing It (Using Java)

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问题描述

我发现并关注了如何读取XML的Stackoverflow(http://stackoverflow.com/questions/2310139/how-to-read-xml-response-from-a-url-in-java)中的示例来自URL的文件(如我在下面粘贴的代码中所示)。我唯一的麻烦是,现在我得到了读取XML的程序,我该如何将它存储起来呢?例如,我是否可以将信息保存到项目中内置的XML文件中(如果可能的话,这对我来说是最好的解决方案)?例如,我在项目中内置了一个空白的XML文件。该程序运行,从URL读取XML代码,并将其全部存储到预先构建的空白XML文件中。我可以这样做吗?

I found and followed an example from Stackoverflow (http://stackoverflow.com/questions/2310139/how-to-read-xml-response-from-a-url-in-java) of how to read an XML file from a URL (as you can see in my code pasted below). My only trouble is that now that I got the program to read the XML, how do I get it to store it? For example, could I make it save the information to a XML file built into the project (this would be the best solution for me, if it's possible)? Such as, take for example, I have a blank XML file built into the project. The program runs, reads the XML code off of the URL, and stores it all into the pre-built blank XML file. Could I do this?

如果我听起来有点混乱或不清楚,请让我澄清一下我在寻找什么。

If I sound confusing or un-clear about anything, just ask me to clarify what I'm looking for.

这是我的代码,如果你想查看我到目前为止的内容:

And here is my code, if you'd like to look at what I have so far:

package xml.parsing.example;

import java.io.IOException;
import java.net.URL;
import java.net.URLConnection;

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerException;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.dom.DOMSource;
import javax.xml.transform.stream.StreamResult;

import org.w3c.dom.Document;
import org.xml.sax.SAXException;

public class XmlParser {
    public static void main (String[] args) throws IOException, ParserConfigurationException, SAXException, TransformerException {
        URL url = new URL("http://totheriver.com/learn/xml/code/employees.xml");
        URLConnection conn = url.openConnection();

        DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
        DocumentBuilder builder = factory.newDocumentBuilder();
        Document doc = builder.parse(conn.getInputStream());

        TransformerFactory tfactory = TransformerFactory.newInstance();
        Transformer xform = tfactory.newTransformer();

        // that’s the default xform; use a stylesheet to get a real one
        xform.transform(new DOMSource(doc), new StreamResult(System.out));
    }
}


推荐答案

非常简单地说:

File myOutput = new File("c:\\myDirectory\\myOutput.xml");
xform.transform(new DOMSource(doc), new StreamResult(myOutput));

这篇关于在线阅读XML并存储它(使用Java)的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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