将`Java.lang.String`转换为`oracle.sql.TIMESTAMPTZ` [英] Convert `Java.lang.String` TO `oracle.sql.TIMESTAMPTZ`
问题描述
我有以下 Java.lang.String 值，表示 String 值 TIMESTAMPTZ 。我需要转换这些 Java.lang.String TO oracle.sql.TIMESTAMPTZ 。
I have these following Java.lang.String values that represents String value of TIMESTAMPTZ. I need to convert these Java.lang.String TO oracle.sql.TIMESTAMPTZ.
"2016-04-19 17:34:43.781 Asia/Calcutta",
"2016-04-30 20:05:02.002 8:00",
"2003-11-11 00:22:15.0 -7:00",
"2003-01-01 02:00:00.0 -7:00",
"2007-06-08 15:01:12.288 Asia/Bahrain",
"2016-03-08 17:17:35.301 Asia/Calcutta",
"1994-11-24 11:57:17.303"
我通过多种方式尝试过它。
I tried it by many ways.
样本1：
使用 SimpleDateFormat
String[] timeZoneValues = new String[]{"2016-04-19 17:34:43.781 Asia/Calcutta", "2016-04-30 20:05:02.002 8:00", "2003-11-11 00:22:15.0 -7:00", "2003-01-01 02:00:00.0 -7:00", "2007-06-08 15:01:12.288 Asia/Bahrain", "2016-03-08 17:17:35.301 Asia/Calcutta", "1994-11-24 11:57:17.303"};
for(String timeZoneValue: timeZoneValues){
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS XXX");
try {
simpleDateFormat.parse(timeZoneValue);
} catch (ParseException e) {
e.printStackTrace();
}
}
抛出异常：
java.text.ParseException: Unparseable date: "2016-04-19 17:34:43.781 Asia/Calcutta"
at java.text.DateFormat.parse(DateFormat.java:357)
示例2：
通过将这些 String 值直接转换为时间戳或
Tried it by converting these String values directly into Timestamp or oracle.sql.TIMESTAMPTZ
String parse = "2016-04-19 17:34:43.781 8:00";
try {
Timestamp timestamp = Timestamp.valueOf("2016-04-19 17:34:43.781 8:00");
}catch (Exception ex){
ex.printStackTrace();
}
例外：
java.lang.NumberFormatException: For input string: "781 8:000"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
at java.lang.Integer.parseInt(Integer.java:492)
at java.lang.Integer.parseInt(Integer.java:527)
at java.sql.Timestamp.valueOf(Timestamp.java:253)
样本3：
String parse = "2016-04-19 17:34:43.781 Asia/Calcutta";
DateTimeFormatter dateTimeFormatter = ISODateTimeFormat.dateTimeNoMillis();
DateTime dateTime = dateTimeFormatter.parseDateTime(parse);
Timestamp timeStamp = new Timestamp(dateTime.getMillis());
例外：
Invalid format: "2016-04-19 17:34:43.781 Asia/Calcutta" is malformed at " 17:34:43.781 Asia/Calcutta"
样本4：
try {
TIMESTAMPTZ timestamptz = new TIMESTAMPTZ(connection, (String) colValue);
}catch (Exception ex){
ex.printStackTrace();
}
例外：
java.lang.IllegalArgumentException: Timestamp format must be yyyy-mm-dd hh:mm:ss[.fffffffff]
at java.sql.Timestamp.valueOf(Timestamp.java:249)
at oracle.sql.TIMESTAMPTZ.toBytes(TIMESTAMPTZ.java:1919)
at oracle.sql.TIMESTAMPTZ.<init>(TIMESTAMPTZ.java:253)
我试图将 TIMESTAMPTZ 值插入 Oracle 使用 Apache Metamodel 的数据库，我的系统上安装了 Java 1.7 。
I am trying to insert the TIMESTAMPTZ value into Oracle database using Apache Metamodel and I have Java 1.7 installed on my system.
推荐答案
您的时间戳不是标准的java可解析格式。因此，为了解析它们，您需要编写用于处理此类格式的自定义代码。
Your timestamps are not in a standard java parseable formats. So in order to parse them you need to write custom code for handling such formats.
观察结果：
Couple of observations:
亚洲/加尔各答不是有效的Parseable TimeZone，因此您需要一些
机制来获得相应的时区。
Asia/Calcutta is not a valid Parseable TimeZone, hence you need some mechanism to get corresponding timezone.
8:00在java中也不是有效的Parseable Timezone，因此你需要
一些机制来将它格式化为有效值+08：00
8:00 is also not a valid Parseable Timezone in java, hence you need some mechanism to format it in a valid value +08:00
牢记以上几点，以下代码将帮助您。
Keeping above points in mind, following code will do the needful for you.
SimpleDateFormat dateFormatTZGeneral = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS z");
SimpleDateFormat dateFormatTZISO = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS XXX");
SimpleDateFormat dateFormatWithoutTZ = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS");
String[][] zoneStrings = DateFormatSymbols.getInstance().getZoneStrings();
Date date = null;
String[] timeStampSplits = timestamp.split(" ");
if(timeStampSplits.length>2) {
String timezone = timeStampSplits[2];
//First Case Asia/Calcutta
if(Character.isAlphabetic(timezone.charAt(timezone.length()-1))) {
for(String[] zoneString: zoneStrings) {
if(zoneString[0].equalsIgnoreCase(timezone)) {
timeStampSplits[2] = zoneString[2];
break;
}
}
timestamp = createString(timeStampSplits," ");
date = getDate(timestamp, dateFormatTZGeneral);
} else {
//Second Case 8:00
timeStampSplits[2] = formatTimeZone(timeStampSplits[2]);
timestamp = createString(timeStampSplits," ");
date = getDate(timestamp, dateFormatTZISO);
}
} else {
// Third Case without timezone
date = getDate(timestamp, dateFormatWithoutTZ);
}
System.out.println(date);
TIMESTAMPTZ oraTimeStamp = new TIMESTAMPTZ(<connection object>,new java.sql.Timestamp(date.getTime());
上面的代码使用以下实用程序方法
Above code uses following utility methods
private static Date getDate(String timestamp, SimpleDateFormat dateFormat) {
Date date = null;
try {
date = dateFormat.parse(timestamp);
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return date;
}
private static String createString(String[] contents, String separator) {
StringBuilder builder = new StringBuilder();
for (String content : contents) {
builder.append(content).append(separator);
}
builder.deleteCharAt(builder.length()-separator.length());
return builder.toString();
}
private static String formatTimeZone(String timeZone) {
String[] timeZoneSplits = timeZone.split(":");
DecimalFormat formatter = new DecimalFormat("+##;-#");
formatter.setMinimumIntegerDigits(2);
timeZoneSplits[0] = formatter.format(Integer.parseInt(timeZoneSplits[0]));
return createString(timeZoneSplits, ":");
}
此代码专门用于满足您的时间戳示例，任何偏差可能不是由此处理，它将需要更多的自定义。
This code is specifically written to cater your timestamp examples, any deviation might not be handled by this and it will need more customization.
希望这可以帮助你。
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