Java中的模式匹配器 [英] Pattern matcher in Java

问题描述

我想要一个像这样的模式匹配器的结果

I want a result from a pattern matcher like this

finalResult = "1. <b>Apple</b> - Apple is a fruit 2. <b>Caw</b> - Caw is an animal 3. <b>Parrot</b> - Parrot is a bird";

我试过这种方式：

        String test = "1. Apple - Apple is a fruit 2. Caw - Caw is an animal 3. Parrot - Parrot is a bird";
        String finalResult = "";

        Pattern pat = Pattern.compile("\\d\\.(.+?)-");
        Matcher mat = pat.matcher(test);

        int count = 0;
        while(mat.find()){
            finalResult += test.replaceAll(mat.group(count), "<b>" + mat.group(count) + "</b>");
            count++;
        }

推荐答案

您可以直接使用 test.replaceAll（）而不是使用 Pattern.matcher（），因为 replaceAll（）自己接受正则表达式。

You can directly use test.replaceAll() instead of using Pattern.matcher(), since replaceAll() accepts regex on its own.

使用的正则表达式就像（？< = \\ d \\。）（\\\\ * *）（？= - ）。

And the regex to use would be like "(?<=\\d\\. )(\\w*?)(?= - )".

DEMO

所以您的代码将是

String test = "1. Apple - Apple is a fruit 2. Caw - Caw is an animal 3. Parrot - Parrot is a bird";
String finalResult = "";
finalResult = test.replaceAll("(?<=\\d\\. )(\\w*?)(?= - )", "<b>" + "$1" + "</b>");

这篇关于Java中的模式匹配器的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！