Android中的PhoneGap退出应用程序时,点击按钮? [英] Exit from app when click button in android phonegap?
本文介绍了Android中的PhoneGap退出应用程序时,点击按钮?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我是新来的PhoneGap。我有prepared一个样本应用程序。我的应用程序有2页,第一页有一个按钮,点击后的第二页将打开。这是使用以下工作正常,
I am new to phonegap. I have prepared one sample application. My application has 2 pages, the first page has one button, when clicked the second page will open. It is working fine using the following
function callAnothePage()
{
window.location = "test.html";
}
第二页有一个按钮,点击时我想从应用程序退出。我用下面的
The second page has one button, when clicked I want to exit from the application. I used the following
function exitFromApp()
{
navigator.app.exitApp();
}
的test.html
code,
<!DOCTYPE html>
<html>
<head>
<script type="text/javascript" charset="utf-8" src="cordova-2.0.0.js"></script>
<script type="text/javascript" charset="utf-8">
function onLoad()
{
console.log("device reday !!!!")
document.addEventListener("deviceready", onDeviceReady, true);
}
function exitFromApp()
{
console.log("in button");
navigator.app.exitApp();
}
</script>
</head>
<body onload="onLoad();">
<h4><center>Login Page</center></h4>
<input type="submit" onclick="exitFromApp()" value="exit"/>
</body>
</html>
但它不能正常工作。
But it is not working.
推荐答案
试试这个code。
<!DOCTYPE HTML>
<html>
<head>
<title>PhoneGap</title>
<script type="text/javascript" charset="utf-8" src="cordova-1.5.0.js"></script>
<script type="text/javascript" charset="utf-8">
function onLoad()
{
document.addEventListener("deviceready", onDeviceReady, true);
}
function exitFromApp()
{
navigator.app.exitApp();
}
</script>
</head>
<body onload="onLoad();">
<button name="buttonClick" onclick="exitFromApp()">Click Me!</button>
</body>
</html>
替换 SRC =科尔多瓦 - 1.5.0.js你的PhoneGap的JS。
Replace src="cordova-1.5.0.js" with your phonegap js .
这篇关于Android中的PhoneGap退出应用程序时,点击按钮?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文