如何获取java中源字符串中大括号内的字符串数组 [英] how to get the array of strings that are inside curly braces in the source string in java

问题描述

java中有一个字符串对象，其内容为：

There is a string object in java with its contents as:

String sourceString="This {is} a sample {string} that {contains} {substrings} inside curly {braces}";

我希望字符串数组的内容为： {is}， {string}，{contains}，{substrings} {braces}

I want the array of string with its contents as: {is},{string},{contains},{substrings}{braces}

以下是我为了获得结果但输出而编写的代码我得到的是：

Following is the code that I wrote to get the result but the output I am getting is:

"{is} a sample {string} that {contains} {substrings} inside curly {braces}"

所以，基本上它是采用第一个开放花括号和最后一个之间的所有字符关闭花括号。

So, basically it is taking all the characters that are in between the first open curly braces and last closing curly braces.

// Source string
String sourceString="This {is} a samle {string} that {contains} {substrings} inside curly {braces}";

// Regular expression to get the values between curly braces (there is a mistake, I guess)
String regex="\\{(.*)\\}";
Matcher matcher = Pattern.compile(regex).matcher(sourceString);

while (matcher.find()) {
    System.out.println(matcher.group(0));
}

推荐答案

发现了一点谷歌搜索此解决方案，它给了我关于模式的想法

A little bit of Googling found this solution, which gave me ideas for the pattern

用课程：正则表达式带来了我需要提供此库的库和库...

Some time spent with Lesson: Regular Expressions brought the libraries and functionality I would need to provide this example...

String exp = "\\{(.*?)\\}";

String value = "This {is} a samle {string} that {contains} {substrings} inside curly {braces}";

Pattern pattern = Pattern.compile(exp);
Matcher matcher = pattern.matcher(value);

List<String> matches = new ArrayList<String>(5);
while (matcher.find()) {
    String group = matcher.group();
    matches.add(group);
}

String[] groups = matches.toArray(new String[matches.size()]);
System.out.println(Arrays.toString(groups));

哪些输出

[{is}, {string}, {contains}, {substrings}, {braces}]

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