随机数发生器 [英] Random Number Generator

问题描述

我需要用Java编写程序，使用以下公式生成[0,1]范围内的随机数：

I need to write a program in Java to generate random numbers within the range [0,1] using the formula:

X _i =（aX _i-1 + b）mod m

X_i = (aX_i-1 + b) mod m

假设a，b&的任何固定int值m和X ₀ = 0.5（即i = 0）

assuming any fixed int values of a, b & m and X₀ = 0.5 (ie i=0)

我该怎么做？

我试过这样做但显然是错误的：

i tried doing this but it's obviously wrong:

int a = 25173, b = 13849, m = 32768;
double X_[i];
for (int i = 1; i<100; i++)
   X_[i] = (a*(X_[i]-1) + b) % m;
double X_[0] = 0.5;
double double = new double();
System.out.println [new double];

推荐答案

以下是一些提示：

int a, d, m, x;

乘法是 * 和 mod 是％。

好的，我会再给你一点提示。你只需要一个X，你不需要所有这些数组;因为你只使用整数，所以你不需要任何浮点数或双重数。

Okay, I'll give you a little more of a hint. You only need one X, you don't need all these arrays; since you're only using integers you don't need any floats or doublts.

重要的代码行将是

x = (a * x + b) % m ;

你不需要另外的 x 那里因为 = 右侧的 x 是OLD x ，或 x _i-1 ;左侧的那个将是您的新 x ，或 x _i 。

You don't need another x there because the x on the right hand side of the = is the OLD x, or x_i-1; the one on the left side will be your "new" x, or x_i.

现在，你需要编写一个Java包装器，它可以让你创建一个方法，这意味着编写一个类 。

Now, from there, you need to write the Java wrapper that will let you make that a method, which means writing a class.

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