HTML表单方法POST调用java servlet的doGet方法 [英] HTML form method POST calls java servlet doGet method
问题描述
我有一个这样的HTML表单：
I have an HTML form like this:
form.html：
form.html:
<html>
<body>
your name is :<br><br>
<form ACTION="../post2" METHOD="POST">
<input name="name" type="text" id="name"/>
<input name="send" type="submit" value="send"/>
</form>
</body>
<html>
提供此请求的servlet：
The servlet to serve this request:
post2.class：
post2.class:
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.http.*;
public class post2 extends HttpServlet
{
protected void doDo(HttpServletRequest request,HttpServletResponse response)
throws IOException{
String name = request.getParameter("name");
response.setContentType("text/html");
PrintWriter out = response.getWriter();
out.println("<HTML><BODY>");
out.println("<H2>hello "+name+"</H2>");
out.println("<BR><BR>");
out.println("info:");
out.println("<BR><BR>");
out.println("<H2>metoda GET</H2>");
out.println("<BR><BR>");
out.println("SERVER_NAME="+request.getServerName()+"<BR>");
out.println("REQUEST_METHOD="+request.getMethod()+"<BR>");
out.println("QUERY_STRING="+request.getQueryString()+"<BR>");
out.println("REMOTE_HOST="+request.getRemoteHost()+"<BR>");
out.println("REMOTE_ADDR="+request.getRemoteAddr());
out.println("</BODY></HTML>");
}
@Override
public void doGet(HttpServletRequest request,HttpServletResponse response)
throws IOException {
doDo(request,response);
}
@Override
public void doPost(HttpServletRequest request,HttpServletResponse response)
throws IOException {
doDo(request,response);
}
}
，结果是：
hello null
info:
SERVER_NAME=localhost
REQUEST_METHOD=GET
QUERY_STRING=null
REMOTE_HOST=127.0.0.1
REMOTE_ADDR=127.0.0.1
出了什么问题？对我来说，似乎servlet没有从表单中看到post方法。请帮忙，我完全不知道为什么它不能正常工作......
what is wrong ? For me it seems that the servlet don't see post method from form. Please help, Im completly have no idea why it not working properly...
来自wireshark的结果：
the result from the wireshark:
648 126.229267 87.105.184.89 192.168.1.100 HTTP 557 POST / post2
HTTP / 1.1（application / x-www-form-urlencoded）
648 126.229267 87.105.184.89 192.168.1.100 HTTP 557 POST /post2 HTTP/1.1 (application/x-www-form-urlencoded)
953 379.456916 192.168.1.100 87.105.184.89 HTTP 239 HTTP / 1.1 302已移动
暂时
953 379.456916 192.168.1.100 87.105.184.89 HTTP 239 HTTP/1.1 302 Moved Temporarily
955 379.462518 192.168.1.100 87.105.184.89 HTTP 470 GET / post2 /
HTTP / 1.1
955 379.462518 192.168.1.100 87.105.184.89 HTTP 470 GET /post2/ HTTP/1.1
957 379.463979 192.168.1.100 87.105.184.89 HTTP 431 HTTP / 1.1 200 OK
（text / html）
957 379.463979 192.168.1.100 87.105.184.89 HTTP 431 HTTP/1.1 200 OK (text/html)
路由逻辑：
tomcat \ webapps\ROOT\form.html - > \ tomcat\webapps \ postt2 \ WEB-INF \classes \ postt2.class
推荐答案
这可能是由于重定向造成的吗？如果/ post2重定向到/ post2 /，您的POST请求将转换为GET，丢失所有发布数据。
Could this be due to a redirect? If "/post2" redirects to "/post2/" your POST request would be transformed into a GET, losing all post data.
尝试直接访问/ post2你的浏览器，看看会发生什么。
Try accessing "/post2" directly in your browser and see what happens.
这篇关于HTML表单方法POST调用java servlet的doGet方法的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
