Java - 将字符串转换为相应的ascii的int？ [英] Java - Convert a String of letters to an int of corresponding ascii?

问题描述

我想将一个字符串转换成一个带有相应ascii的int，假设abc：在本例中， 979899 。

I want to convert a String, lets say "abc", to an int with the corresponding ascii: in this example, 979899.

我遇到两个问题：

1）我只写了什么适用于ascii长两个字符且

1) what I wrote only works for characters whose ascii is two characters long and

2）的字符，因为这些数字非常大，我不能使用longs而且我在使用BigIntegers时遇到了麻烦。

2) since these numbers get very big, I can't use longs and I'm having trouble utilizing BigIntegers.

这是我到目前为止：

BigInteger mInt = BigInteger.valueOf(0L);
for (int i = 0; i<mString.length(); i++) {
        mInt = mInt.add(BigInteger.valueOf(
                (long)(mString.charAt(i)*Math.pow(100,(mString.length()-1-i)))));
}

任何建议都会很棒，谢谢！

Any suggestions would be great, thanks!

推荐答案

首先使用 StringBuilder 进行所有连接，然后创建 BigInteger 结果出来了吗？这似乎比你现在做的要简单得多。

What's wrong with doing all the concatenation first with a StringBuilder and then creating a BigInteger out of the result? This seems to be much simpler than what you're currently doing.

String str = "abc";  // or anything else

StringBuilder sb = new StringBuilder();
for (char c : str.toCharArray())
    sb.append((int)c);

BigInteger mInt = new BigInteger(sb.toString());
System.out.println(mInt);

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