在Eclipse插件中打开文件到某一行 [英] Open file to a certain line in Eclipse plugin

问题描述

我正在编写一个插件，当按下按钮时必须在某一行打开文件。
我有以下代码在某一行打开文件。

I am writting a plugin that has to open a file at a certain line when a button is pressed. I have the following code to open the file at a certain line.

        String filePath = "file path" ;
            final IFile inputFile = ResourcesPlugin.getWorkspace().getRoot().getFileForLocation(Path.fromOSString(filePath));
            if (inputFile != null) {
                IWorkbenchPage page1 = PlatformUI.getWorkbench().getActiveWorkbenchWindow().getActivePage();
                IEditorPart openEditor11 = IDE.openEditor(page1, inputFile);
            }


            int Line = 20;

                    if (openEditor11 instanceof ITextEditor) {
                        ITextEditor textEditor = (ITextEditor) openEditor ;
                        IDocument document= textEditor.getDocumentProvider().getDocument(textEditor.getEditorInput());
                        textEditor.selectAndReveal(document.getLineOffset(Line - 1), document.getLineLength(Line-1));
                    }

我的问题是if语句中的变量openEditor11给出错误：openEditor11无法解析为变量。可能是什么问题？

My problem is that the variable openEditor11 in the if statement gives the error: openEditor11 cannot be resolved to a variable. What can be the problem ?

推荐答案

根据 https://wiki.eclipse.org/FAQ_How_do_I_open_an_editor_on_a_file_in_the_workspace%3F

int lineNumber = ...
IPath path = ...
IFile file = ResourcesPlugin.getWorkspace().getRoot().getFile(path);
IMarker marker = file.createMarker(IMarker.TEXT);
marker.setAttribute(IMarker.LINE_NUMBER, lineNumber);
IWorkbenchPage page = PlatformUI.getWorkbench().getActiveWorkbenchWindow().getActivePage();
IDE.openEditor(page, marker);
marker.delete();

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