在Java中使用char作为无符号16位值？ [英] Using char as an unsigned 16 bit value in Java?

问题描述

我需要Java中的无符号8位整数，而char似乎是唯一接近它的东西。虽然它的大小是它的两倍，但是它是无符号的，这使得它可以用于我想要的东西（编写一个需要无符号字节的基本仿真器）。问题是我听过其他程序员说不应该以这种方式使用char，而应该只使用int。这是真的，为什么会这样？

I need an unsigned 8 bit integer in Java, and char seems to be the only thing close to that. Although it's double the size, it's unsigned which makes it practical for what I want to use it for (writing a basic emulator which requires unsigned bytes). The problem is that I've heard other programmers say that one shouldn't use char in that manner and should just use int or so. Is this true, and why so?

推荐答案

如果你需要一个无符号的8位整数，那么使用 byte 。在arithemtic操作中（实际上标记的重要性）很容易使其无符号为 byteValue& 0xFF

If you need an unsigned 8 bit integer then use byte. It's easy to make it unsigned in arithemtic operations (where actually sign matters) as byteValue & 0xFF

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