如何跳过Stream< String>的偶数行从Files.lines获得 [英] How to skip even lines of a Stream<String> obtained from the Files.lines

问题描述

在这种情况下，奇数行只有有意义的数据，并且没有唯一标识这些行的字符。我的目的是获得与以下示例等效的内容：

In this case just odd lines have meaningful data and there is no character that uniquely identifies those lines. My intention is to get something equivalent to the following example:

Stream<DomainObject> res = Files.lines(src)
     .filter(line -> isOddLine())
     .map(line -> toDomainObject(line))

在没有共享全局状态的情况下，有没有干净的方法呢？

Is there any "clean" way to do it, without sharing global state?

推荐答案

一个干净的方法是更深层次并实现 Spliterator 。在这个级别上，您可以控制流元素的迭代，只需在下游请求一个项目时迭代两个项目：

A clean way is to go one level deeper and implement a Spliterator. On this level you can control the iteration over the stream elements and simply iterate over two items whenever the downstream requests one item:

public class OddLines<T> extends Spliterators.AbstractSpliterator<T>
    implements Consumer<T> {

    public static <T> Stream<T> oddLines(Stream<T> source) {
        return StreamSupport.stream(new OddLines(source.spliterator()), false);
    }
    private static long odd(long l) { return l==Long.MAX_VALUE? l: (l+1)/2; }
    Spliterator<T> originalLines;

    OddLines(Spliterator<T> source) {
        super(odd(source.estimateSize()), source.characteristics());
        originalLines=source;
    }

    @Override
    public boolean tryAdvance(Consumer<? super T> action) {
        if(originalLines==null || !originalLines.tryAdvance(action))
            return false;
        if(!originalLines.tryAdvance(this)) originalLines=null;
        return true;
    }

    @Override
    public void accept(T t) {}
}

然后你就可以使用它了

Stream<DomainObject> res = OddLines.oddLines(Files.lines(src))
    .map(line -> toDomainObject(line));

此解决方案没有副作用，并保留了 Stream的大部分优势 API就像懒惰评估一样。但是，应该很清楚它对于无序流处理没有有用的语义（注意使用 forEachOrdered 而不是 forEach的微妙方面） / code>在对所有元素执行终端操作时）并且原则上支持并行处理时，它不太可能非常有效...

This solution has no side effects and retains most advantages of the Stream API like the lazy evaluation. However, it should be clear that it hasn’t a useful semantics for unordered stream processing (beware about the subtle aspects like using forEachOrdered rather than forEach when performing a terminal action on all elements) and while supporting parallel processing in principle, it’s unlikely to be very efficient…

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