Android摄像头 - 我如何可以采取一个特定的＆QUOT;矩形＆QUOT;从字节数组？ [英] Android Camera - How can i take a specific "rectangle" from the byte array?

问题描述

我已经创建了拍摄并保存照片的应用程序。 我有一个preVIEW和重要的是preVIEW顶部覆盖。 叠加定义了一个正方形（广场周围的区域显示了preVIEW有点暗），因为你可以在图片中看到：

I have created an application that shoots and saves photos. I have a preview and an overlay on top of that preview. The overlay defines a square (the area around the square shows the preview a bit darker), as you can see in the image:

例如

我需要做的是提取其中方是图像的一部分。 方形的定义是这样的：

What i need to do is to extract the part of the image where the square is. The square is defined like this:

    Rect frame = new Rect(350,50,450,150);

我怎样才能做到这一点？我有一个字节数组（byte []的数据），我可以节省，但我想更改应用程序，以便只有方形区域将被保存。

How can i do that? i have the byte array (byte[] data) that i can save, but i want to change the application so that only the square area will be saved.

编辑：我已经试过如下：

i have tried the following:

int[] pixels = new int[100000];
            ByteArrayOutputStream bos = new ByteArrayOutputStream();
            Bitmap bitmap = BitmapFactory.decodeByteArray(data , 0, data.length);
            bitmap.getPixels(pixels, 0, 480, 350, 50, 100, 100);
            bitmap = Bitmap.createBitmap(pixels, 0, 100, 100, 100, Config.ARGB_4444);
            bitmap.compress(CompressFormat.JPEG, 0, bos);
            byte[] square = bos.toByteArray();

，然后写入阵列广场，以一个新的文件... 问题是，我得到发行的画面......有一个与我所做的转型问题

and then write the array "square" to a new file... The problem is that i get a picture made of lines... there is a problem with the transformation that i made

推荐答案

我花了一些时间来弄清楚，在code应该是这样的：

It took me some time to figure out that the code should look like this:

int[] pixels = new int[100*100];//the size of the array is the dimensions of the sub-photo
        ByteArrayOutputStream bos = new ByteArrayOutputStream();
        Bitmap bitmap = BitmapFactory.decodeByteArray(data , 0, data.length);
        bitmap.getPixels(pixels, 0, 100, 350, 50, 100, 100);//the stride value is (in my case) the width value
        bitmap = Bitmap.createBitmap(pixels, 0, 100, 100, 100, Config.ARGB_8888);//ARGB_8888 is a good quality configuration
        bitmap.compress(CompressFormat.JPEG, 100, bos);//100 is the best quality possibe
        byte[] square = bos.toByteArray();

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