如何手动创建multipart / form-data [英] How to manually create multipart/form-data
本文介绍了如何手动创建multipart / form-data的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我们可以使用 .formData()
Body
mixin在 FormData 数据表示/ Body / formData#Browser_compatibilityrel =nofollow noreferrer> Chromium(Chrome)60+和Firefox 39+
We can use .formData()
of Body
mixin to return a FormData
representation of data at Chromium (Chrome) 60+ and Firefox 39+
相关规格:
- 7.2 The Multipart Content-Type
- Returning Values from Forms: multipart/form-data
勘误表
- Clarification of Body package data algorithm with bytes, FormData and multipart/form-data MIME type #392
- Documenting de-facto handling of multipart/form-data form field file uploads #3040
相关
- Multipart HTTP response
- How to upload files in Web Workers when FormData is not defined
如何在客户端和服务器上使用JavaScript手动创建 multipart / form-data
提供 multipart / form-data
作为回复?
How to manually create multipart/form-data
using JavaScript at client and at server to serve the multipart/form-data
as a response?
推荐答案
您可以使用XMLHttpRequest手动创建 multipart / form-data
这个例子。
You can create multipart/form-data
manually with XMLHttpRequest like this example.
function multiPost(method, url, formHash){
var boundary = "nVenJ7H4puv"
var body = ""
for(var key in formHash){
body += "--" + boundary
+ "\r\nContent-Disposition: form-data; name=" + formHash[key].name
+ "\r\nContent-type: " + formHash[key].type
+ "\r\n\r\n" + formHash[key].value + "\r\n"
}
body += "--" + boundary + "--\r\n"
var xml = new XMLHttpRequest();
xml.open(method, url)
xml.setRequestHeader("Content-Type", "multipart/form-data; boundary=" + boundary)
xml.setRequestHeader("Content-Length", body.length)
xml.send(body)
}
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