如何初始化和打印unicode字符？ [英] how to initial and print the unicode character?
问题描述
我想尝试ANSI C99的unicode功能。所以我写了一个测试程序。
函数很简单，但我无法用windows cp sp2下的dev c ++ 4.9.9.2
编译它，因为编译器总是认为
初始化wchar_t字符串是非法的。这是我的功能：
#include< stdio.h>
#include< stdlib.h>
#include< wchar .h>
#include< wctype.h>
#include< string.h>
int main（ int argc，char * argv []）
{
wchar_t * cur_buff = L" X";
wprintf（cur_buff）;
返回0;
}
函数中，wchar_t * cur_buff的初始化为LX，如果X
是一个ascii字符，然后所有东西都运行良好。但是如果X是一个非中文字符的非ascii字符，编译器会警告这是一个非法的字节序列。源文件保存为ascci
代码，字符集为gb2312。我想知道为什么会这样？
i want to try ANSI C99''s unicode fuctions. so i write a test program.
the function is simple, but i cannot compile it with dev c++ 4.9.9.2
under windows xp sp2, since the compiler always think that the
initialization of the wchar_t string is illegal. here is my function:
#include <stdio.h>
#include <stdlib.h>
#include <wchar.h>
#include <wctype.h>
#include <string.h>
int main(int argc, char *argv[])
{
wchar_t *cur_buff=L"X";
wprintf(cur_buff);
return 0;
}
in the function, the initialization of wchar_t *cur_buff is L"X", if X
is an ascii character, then all things function well. But if X is
non-ascii charater such as a Chinese character, compiler would alert
that this is a illegal byte sequence. The source file is saved as ascci
code, and the character set is gb2312. i wonder why this happens?
推荐答案
2006-07-04，wizardyhnr< wi ******** @ gmail.comwrote：
On 2006-07-04, wizardyhnr <wi********@gmail.comwrote:
i想尝试ANSI C99的unicode功能。所以我写了一个测试程序。
函数很简单，但我无法用windows cp sp2下的dev c ++ 4.9.9.2
编译它，因为编译器总是认为
初始化wchar_t字符串是非法的。这是我的功能：
i want to try ANSI C99''s unicode fuctions. so i write a test program.
the function is simple, but i cannot compile it with dev c++ 4.9.9.2
under windows xp sp2, since the compiler always think that the
initialization of the wchar_t string is illegal. here is my function:
如果不看你的实际问题，这里有一些提示：
1）这是公平的不太可能你真的有一个C99编译器。
2）用C ++这个词来表达的东西是不太可能的。在其中
甚至是C编译器，更不用说是C99编译器了。
除此之外，我们不关心你有什么操作系统或平台。我们在这里讨论了
标准C，这个平台是独立的。
-
Andrew Poelstra< http： //www.wpsoftware.net/blog>
要给我发电子邮件，请使用apoelstra。在上面的地址。
你们人讨厌数学。 - James Harris
Without looking at your actual problem, here''s a few tips:
1) It''s fairly unlikely that you actually have a C99 compiler.
2) It''s very unlikely that something with the word "C++" in it
is even a C compiler, let alone a C99 compiler.
Other than that, we don''t care what OS or platform you have. We discuss
standard C here, and that''s platform independant.
--
Andrew Poelstra <http://www.wpsoftware.net/blog>
To email me, use "apoelstra" at the above address.
"You people hate mathematics." -- James Harris
* wizardyhnr：
* wizardyhnr:
我想尝试ANSI C99的unicode功能。所以我写了一个测试程序。
函数很简单，但我无法用windows cp sp2下的dev c ++ 4.9.9.2
编译它，因为编译器总是认为
初始化wchar_t字符串是非法的。这是我的功能：
#include< stdio.h>
#include< stdlib.h>
#include< wchar .h>
#include< wctype.h>
#include< string.h>
int main（ int argc，char * argv []）
{
wchar_t * cur_buff = L" X";
wprintf（cur_buff）;
返回0;
}
函数中，wchar_t * cur_buff的初始化为LX，如果X
是一个ascii字符，然后所有东西都运行良好。但是如果X是一个非中文字符的非ascii字符，编译器会警告这是一个非法的字节序列。源文件保存为ascci
代码，字符集为gb2312。我想知道为什么会这样？
i want to try ANSI C99''s unicode fuctions. so i write a test program.
the function is simple, but i cannot compile it with dev c++ 4.9.9.2
under windows xp sp2, since the compiler always think that the
initialization of the wchar_t string is illegal. here is my function:
#include <stdio.h>
#include <stdlib.h>
#include <wchar.h>
#include <wctype.h>
#include <string.h>
int main(int argc, char *argv[])
{
wchar_t *cur_buff=L"X";
wprintf(cur_buff);
return 0;
}
in the function, the initialization of wchar_t *cur_buff is L"X", if X
is an ascii character, then all things function well. But if X is
non-ascii charater such as a Chinese character, compiler would alert
that this is a illegal byte sequence. The source file is saved as ascci
code, and the character set is gb2312. i wonder why this happens?
不知道C，但是在C ++中你必须在那里放一个'const'，
wchar_t const * curr_buff = L" X";
-
答：因为它弄乱了人们通常阅读的顺序文字。
问：为什么这么糟糕？
A：热门帖子。
问：什么是最烦人的事情在usenet和电子邮件中？
Don''t know about C, but in C++ you''d have to put a ''const'' in there,
wchar_t const* curr_buff = L"X";
--
A: Because it messes up the order in which people normally read text.
Q: Why is it such a bad thing?
A: Top-posting.
Q: What is the most annoying thing on usenet and in e-mail?
" Alf P. Steinbach" < al *** @ start.nowrites：
"Alf P. Steinbach" <al***@start.nowrites:
* wizardyhnr：
* wizardyhnr:
> wchar_t * cur_buff = LX;
> wchar_t *cur_buff=L"X";
不知道C，但是在C ++中你必须在那里放一个'const'，
wchar_t const * curr_buff = LX;
Don''t know about C, but in C++ you''d have to put a ''const'' in there,
wchar_t const* curr_buff = L"X";
不在C中。
-
它不会是新的C标准如果它没有给静态这个词带来新的含义。
- C99上的彼得斯巴赫
Not in C.
--
"It wouldn''t be a new C standard if it didn''t give a
new meaning to the word `static''."
--Peter Seebach on C99
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