指向自己的指针 [英] pointer to itself

问题描述

int main（）

{

int * i =（int *）& i;

}


上述声明是按照标准的有效声明吗？

由于对象正在创建，同时我试图存储

其地址本身，这是正确的事情吗？

解决方案

shaanxxx写道：

int main（）

{

int * i =（int *）& i ;

}


上面的语句是按照标准的有效声明吗？

因为对象正在创建，同时我也是试图将其地址存储起来，这是正确的事情吗？

好​​吧，没有错。没有什么能阻止你这样做。

shaanxxx写道：

int main（）

{

int * i =（int *）& i;

}


上面的语句是按照标准的有效语句吗？

由于对象是在创建的，同时我试图将其地址存储为自己的地址，这是对的吗？

这是实现定义的行为，因为你初始化我的

是一个不兼容的指针值。我的意思是只持有int指针

值。你正在为它指定一个类型指针的指针值，指向

指向int的指针。

3月4日，8日：17 pm，shaanxxx < shaan ... @ yahoo.comwrote：

int main（）

{

int * i =（int *）& i;


}


上述声明是否符合标准的有效声明？

由于对象正在创建，同时我试图将其地址存储在其中，这是正确的事情吗？

我猜可能存在对齐问题。

如果我错了，请纠正我。

int main()
{
int *i = (int *) &i;
}

Above statement is a valid statement as per standard ?
Since object is getting created and same time i am trying to store
its address in itself, it is right thing to do?

解决方案

shaanxxx wrote:

int main()
{
int *i = (int *) &i;
}

Above statement is a valid statement as per standard ?
Since object is getting created and same time i am trying to store
its address in itself, it is right thing to do?

Well, nothing was wrong. Nothing prevents you doing that.

shaanxxx wrote:

int main()
{
int *i = (int *) &i;
}

Above statement is a valid statement as per standard ?
Since object is getting created and same time i am trying to store
its address in itself, it is right thing to do?

It''s implementation defined behaviour since your initialising i with
an incompatible pointer value. i is meant only to hold int pointer
values. You''re focibly assigning it a pointer value of type pointer to
pointer to int.

On Mar 4, 8:17 pm, "shaanxxx" <[e-mail]:

int main()
{
int *i = (int *) &i;

}

Above statement is a valid statement as per standard ?
Since object is getting created and same time i am trying to store
its address in itself, it is right thing to do?

I guess there can be alignment issues.
Correct me if I''m wrong.

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