正则表达式 [英] Regexp
问题描述
我在regexp方面很弱，但希望有人在这种情况下知道。
我想尝试这样的网址：
something.lasso？blah = blah& blah2 = blah2& sort = hello& b lah3 = blah3
并删除& sort = XXX而不会伤害其余网址。要替换的参数
将是传递给函数的参数。这是我到目前为止所获得的
：
函数刷新（项目）{
current = document.location.href;
if（current.match（item.name +''=''））
//伪代码在这里
//current.replace （item.name regexp，''''）;
return（当前+"&" + item.name +" =" + item.value）;
这个函数将被解雇：
All< input type =" radio"名称= QUOT;显示" value =" all"
onclick =" document.location = refresh（this）;">
Mine< input type =" radio"名称= QUOT;显示" value =" mine"
onclick =" document.location = refresh（this）;">
如有任何建议，敬请谅解！
-S
I am weak when it comes to regexp but hoped someone might know in this case.
I am trying to take a url like this :
something.lasso?blah=blah&blah2=blah2&sort=hello&b lah3=blah3
And remove the &sort=XXX without hurting the rest of the url. The parameter
to be replaced would be a parameter passed to a function. Here is what I
have so far:
function refresh(item) {
current = document.location.href;
if(current.match(item.name+''=''))
//pseudo code here
//current.replace(item.name regexp , '''');
return (current + "&" + item.name + "=" + item.value);
This function would be fired like this :
All <input type="radio" name="show" value="all"
onclick="document.location=refresh(this);">
Mine <input type="radio" name="show" value="mine"
onclick="document.location=refresh(this);">
Any suggestions are appreciated!
-S
推荐答案
Phat G5（G3）于2005年12月26日在comp.lang.javascript中写道< b> ：
Phat G5 (G3) wrote on 26 dec 2005 in comp.lang.javascript:
关于regexp，我很弱，但希望有人可能知道这个案例。我想尝试这样的网址：
something.lasso？blah = blah& blah2 = blah2& sort = hello& b lah3 = blah3
并删除& ; sort = XXX而不会伤害其余网址。要替换的
参数将是传递给函数的参数。
I am weak when it comes to regexp but hoped someone might know in this
case. I am trying to take a url like this :
something.lasso?blah=blah&blah2=blah2&sort=hello&b lah3=blah3
And remove the &sort=XXX without hurting the rest of the url. The
parameter to be replaced would be a parameter passed to a function.
str =''something.lasso？blah = blah& blah2 = blah2&排序=你好&安培; blah3 = blah3''
alert（str）
str = str.replace（/ sort = [^&] *& ？/，''''）
alert（str）
-
Evertjan。
荷兰。
（请在我的电子邮件地址中将x'变为点数）
str = ''something.lasso?blah=blah&blah2=blah2&sort=hello& blah3=blah3''
alert(str)
str = str.replace(/sort=[^&]*&?/,'''')
alert(str)
--
Evertjan.
The Netherlands.
(Please change the x''es to dots in my emailaddress)
Evertjan。 2005年12月26日在comp.lang.javascript中写道 ：
Evertjan. wrote on 26 dec 2005 in comp.lang.javascript:
Phat G5（G3）于2005年12月26日在comp.lang.javascript中写道 ：
Phat G5 (G3) wrote on 26 dec 2005 in comp.lang.javascript:
我对regexp很弱，但希望有人可能知道这个案例。我想尝试这样的网址：
something.lasso？blah = blah& blah2 = blah2& sort = hello& b lah3 = blah3
并删除& ; sort = XXX而不会伤害其余网址。要替换的
参数是传递给函数的参数。
I am weak when it comes to regexp but hoped someone might know in this
case. I am trying to take a url like this :
something.lasso?blah=blah&blah2=blah2&sort=hello&b lah3=blah3
And remove the &sort=XXX without hurting the rest of the url. The
parameter to be replaced would be a parameter passed to a function.
str =''something.lasso？blah = blah& blah2 = blah2& sort = hello& blah3 = blah3''
警报（str）
str = str.replace（/ sort = [^&] *&？/，''''）
alert（str）
str = ''something.lasso?blah=blah&blah2=blah2&sort=hello& blah3=blah3''
alert(str)
str = str.replace(/sort=[^&]*&?/,'''')
alert(str)
对不起，不对，发送按钮太快按下了，试试这个：
str =''something.lasso？blah = blah& blah2 = blah2& sort = hello& blah3 = blah3''
str = str.replace（/&？sort = [^&] * /，''''）
alert（str）
str =''something.lasso？blah = blah& blah2 = blah2& sort = hello''
str = str.replace（/&？sort = [^&] * /，''''）
alert（str）
-
Evertjan。
荷兰。
（请将x''es更改为我的电子邮件地址中的点数）
Sorry, incorrect, the send button was pressed too soon, try this:
str = ''something.lasso?blah=blah&blah2=blah2&sort=hello& blah3=blah3''
str = str.replace(/&?sort=[^&]*/,'''')
alert(str)
str = ''something.lasso?blah=blah&blah2=blah2&sort=hello''
str = str.replace(/&?sort=[^&]*/,'''')
alert(str)
--
Evertjan.
The Netherlands.
(Please change the x''es to dots in my emailaddress)
，文章Xn********************@194.109.133.242，Evertjan。在
ex ************** @ interxnl .net 于12/26/05 8:19 AM写道：
in article Xn********************@194.109.133.242, Evertjan. at
ex**************@interxnl.net wrote on 12/26/05 8:19 AM:
Evertjan。 2005年12月26日在comp.lang.javascript中写道 ：
Evertjan. wrote on 26 dec 2005 in comp.lang.javascript:
Phat G5（G3）于2005年12月26日在comp.lang.javascript中写道 ：
Phat G5 (G3) wrote on 26 dec 2005 in comp.lang.javascript:
我对regexp很弱，但希望有人可能知道这个案例。我想尝试这样的网址：
something.lasso？blah = blah& blah2 = blah2& sort = hello& b lah3 = blah3
并删除& ; sort = XXX而不会伤害其余网址。要替换的
参数是传递给函数的参数。
I am weak when it comes to regexp but hoped someone might know in this
case. I am trying to take a url like this :
something.lasso?blah=blah&blah2=blah2&sort=hello&b lah3=blah3
And remove the &sort=XXX without hurting the rest of the url. The
parameter to be replaced would be a parameter passed to a function.
str =''something.lasso？blah = blah& blah2 = blah2& sort = hello& blah3 = blah3''
警报（str）
str = str.replace（/ sort = [^&] *&？/，''''）
alert（str）
str = ''something.lasso?blah=blah&blah2=blah2&sort=hello& blah3=blah3''
alert(str)
str = str.replace(/sort=[^&]*&?/,'''')
alert(str)
抱歉，不正确，发送按钮过早按下，试试这个：
str =' something.lasso等等=等等&安培; blah2 = blah2&安培;排序=你好&安培; blah3 = blah3''
str = str.replace（/&？sort = [^&] * /，''''）
alert（str）
str =''something.lasso？blah = blah& blah2 = blah2& sort = hello''
str = str.replace（/&？sort = [ ^&] * /，''''）
alert（str）
Sorry, incorrect, the send button was pressed too soon, try this:
str = ''something.lasso?blah=blah&blah2=blah2&sort=hello& blah3=blah3''
str = str.replace(/&?sort=[^&]*/,'''')
alert(str)
str = ''something.lasso?blah=blah&blah2=blah2&sort=hello''
str = str.replace(/&?sort=[^&]*/,'''')
alert(str)
我很欣赏这一点。它几乎完美。我的ISP显然发送速度很快但是b $ b收到了SLOW。我在30分钟前看到谷歌的反应。无论如何，我已经玩过它并发现了一个很小的难度。我试图将
变量放入reg exp中，就像我在公式中看到的那样。我试过各种各样的差异，比如
str =''something.lasso？blah = blah& blah2 = blah2& sort = hello''
item =" sort";
// str = str.replace（/&？sort = [^&] * /，'''' '）
// str2 = eval（" /&？" + item +" = [^&] * /"）;
str3 = /&？（item）= [^&] * /;
alert（str3）;
// str2 = new RegExp（str3，" gi" ;）;
str = str.replace（str3，''''）
alert（str）
如何将评估变量放入正则表达式？
-S
I appreciate this. It almost perfect. My ISP apparently sends fast but
receives SLOW. I saw the response on google over 30 minutes ago. Anyhow, I
have been playing with it and have found a small difficulty. I am trying to
place a variable into the reg exp as you may have seen in my formula. I
tried all sorts of variances like
str = ''something.lasso?blah=blah&blah2=blah2&sort=hello''
item="sort";
//str = str.replace(/&?sort=[^&]*/,'''')
//str2 = eval("/&?" + item + "=[^&]*/");
str3 = /&?(item)=[^&]*/;
alert(str3);
//str2 = new RegExp(str3, "gi");
str = str.replace(str3,'''')
alert(str)
How do I get the evaluated variable into the regexp?
-S
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