的ServerSocket.accept()抛出SocketTimeoutException如果与空消息 [英] ServerSocket.accept() throwing SocketTimeoutException with null message
问题描述
我想从ServerSocket对象获得的Socket的实例。但是,它始终打印
SocketTimeoutException如果= NULL
还有就是我的code:
尝试{
//我们倾听新的连接
Log.d(ShairPort,服务>>在TRY);
尝试 {
servSock =新的ServerSocket(端口);
}赶上(IOException异常E){
Log.d(ShairPort,服务>>在TRY#IO异常=+ e.getMessage());
servSock =新的ServerSocket();
}赶上(例外五){
Log.d(ShairPort,服务>>在TRY·E xception =+ e.getMessage());
}
// DNS发射器(卓悦)
byte []的HWADDR = getHardwareAdress();
发射器=新BonjourEmitter(姓名,getStringHardwareAdress(HWADDR),口);
//设置超时
servSock.setSoTimeout(10000);
Log.d(ShairPort,服务>> stopThread =+ stopThread);
而(!stopThread){
尝试 {
// **********这是抛出异常*************** //
Socket套接字= servSock.accept();
servSock.setReuseAddress(真正的);
Log.d(ShairPort,服务>>接到连接+ socket.toString());
新的RTS presponder(HWADDR,插座)。开始();
}赶上(SocketTimeoutException如果E){
e.printStackTrace();
Log.d(ShairPort,服务>> SocketTimeoutException如果=+ e.getMessage());
// *********在这里我得到异常************** //
}赶上(例外五){
Log.d(ShairPort,服务>>异常=+ e.getMessage());
servSock.close();
}
}
}赶上(IOException异常E){
Log.d(ShairPort,服务>>尽量#CATCH IOException异常=+ e.getMessage());
抛出新的RuntimeException(E);
}
请让我知道如果我做错什么,这样我就可以解决这个问题。
02-06 18:14:08.300:W / System.err的(2245):java.net.SocketTimeoutException
02-06 18:14:08.300:W / System.err的(2245):在java.net.PlainSocketImpl.accept(PlainSocketImpl.java:108)
02-06 18:14:08.300:W / System.err的(2245):在java.net.ServerSocket.implAccept(ServerSocket.java:203)
02-06 18:14:08.310:W / System.err的(2245):在java.net.ServerSocket.accept(ServerSocket.java:128)
02-06 18:14:08.310:W / System.err的(2245):在vavi.apps.shairport.LaunchThread.run(LaunchThread.java:99)
02-06 18:14:08.310:W / System.err的(2245):libcore.io.ErrnoException:产生的原因接受失败:EAGAIN(再试)
02-06 18:14:08.320:W / System.err的(2245):在libcore.io.Posix.accept(本机方法)
02-06 18:14:08.320:W / System.err的(2245):在libcore.io.BlockGuardOs.accept(BlockGuardOs.java:55)
02-06 18:14:08.320:W / System.err的(2245):在java.net.PlainSocketImpl.accept(PlainSocketImpl.java:98)
02-06 18:14:08.320:W / System.err的(2245):... 3更多
您正在设置服务器套接字十秒时间已过。
在接受()
方法,因此将抛出一个 SocketTimeoutException如果
如果没有连接十秒内到达。
如果你不希望这样的行为,不设置超时时间,或提高了。
我不知道为什么你在获得当你自己设定在超过一定时间感到惊讶。
注:这是毫无意义的叫 setReuseAddress()
上的服务器套接字就势必之后,更别说你接受一个新的连接每次。
I am trying to get an instance of Socket from ServerSocket Object. But, it always prints
SocketTimeoutException = null
There is my code:
try {
// We listen for new connections
Log.d("ShairPort", "Service >> In TRY ");
try {
servSock = new ServerSocket(port);
} catch (IOException e) {
Log.d("ShairPort", "Service >> In TRY # IO Exception = " +e.getMessage());
servSock = new ServerSocket();
}catch(Exception e) {
Log.d("ShairPort", "Service >> In TRY # E xception = " +e.getMessage());
}
// DNS Emitter (Bonjour)
byte[] hwAddr = getHardwareAdress();
emitter = new BonjourEmitter(name, getStringHardwareAdress(hwAddr), port);
//Setting Timeout
servSock.setSoTimeout(10000);
Log.d("ShairPort", "Service >> stopThread = " +stopThread);
while (!stopThread) {
try {
//********** This is throwing Exception ***************//
Socket socket = servSock.accept();
servSock.setReuseAddress(true);
Log.d("ShairPort", "Service >> got connection from " + socket.toString());
new RTSPResponder(hwAddr, socket).start();
} catch(SocketTimeoutException e) {
e.printStackTrace();
Log.d("ShairPort", "Service >> SocketTimeoutException = " + e.getMessage());
//********* here I am getting exception **************//
}catch(Exception e) {
Log.d("ShairPort", "Service >> Exception = " + e.getMessage());
servSock.close();
}
}
} catch (IOException e) {
Log.d("ShairPort", "Service >> TRY # CATCH IOException = " + e.getMessage());
throw new RuntimeException(e);
}
Please let me know if I am doing anything wrong, so that I can resolve this issue.
02-06 18:14:08.300: W/System.err(2245): java.net.SocketTimeoutException
02-06 18:14:08.300: W/System.err(2245): at java.net.PlainSocketImpl.accept(PlainSocketImpl.java:108)
02-06 18:14:08.300: W/System.err(2245): at java.net.ServerSocket.implAccept(ServerSocket.java:203)
02-06 18:14:08.310: W/System.err(2245): at java.net.ServerSocket.accept(ServerSocket.java:128)
02-06 18:14:08.310: W/System.err(2245): at vavi.apps.shairport.LaunchThread.run(LaunchThread.java:99)
02-06 18:14:08.310: W/System.err(2245): Caused by: libcore.io.ErrnoException: accept failed: EAGAIN (Try again)
02-06 18:14:08.320: W/System.err(2245): at libcore.io.Posix.accept(Native Method)
02-06 18:14:08.320: W/System.err(2245): at libcore.io.BlockGuardOs.accept(BlockGuardOs.java:55)
02-06 18:14:08.320: W/System.err(2245): at java.net.PlainSocketImpl.accept(PlainSocketImpl.java:98)
02-06 18:14:08.320: W/System.err(2245): ... 3 more
You're setting a ten second timeout on the server socket.
The accept()
method will therefore throw a SocketTimeoutException
if no connection arrives within ten seconds.
If you don't want that behaviour, don't set the timeout, or raise it.
I have no idea why you're surprised at getting a timeout when you're setting it yourself.
NB It is utterly pointless to call setReuseAddress()
on the server socket after it is bound, let alone every time you accept a new connection.
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