格式化字符串 [英] Format Strings

问题描述

任何人都知道为什么s等于0.0870000000000000000000以下

行执行后？


谢谢，

Nate


double d = 0.087000000000000008;

string s = string.Format（" {0：f22}"，d）;

解决方案

" 0870000000000000000000"长度为22


0：f＃ - >固定点＃长度，未指定＃是2我认为

如果你只想要0.87

然后只需使用0：f


Nathan Wiegman <的Na *********** @ discussions.microsoft.com>在消息中写道

news：45 ********************************** @ microsof t.com ...

任何人都知道为什么s等于0.0870000000000000000000在以下
行执行之后？

谢谢，
Nate

double d = 0.087000000000000008;
string s = string.Format（" ; {0：f22}"，d）;

拼写


"如果你只是想要0.87" < - 这应该是0.08

" Du" < 6 ******* @ hotmail.com>在消息中写道

新闻：IK ******************** @ rogers.com ...

" ; 0870000000000000000000"长度为22

0：f＃ - >固定点＃长度，未指定＃是2我认为

如果你只想要0.87
那么只需使用0：f

Nathan Wiegman <的Na *********** @ discussions.microsoft.com>在
消息新闻中写道：45 ********************************** @ microsof t.com。 ..

任何人都知道为什么s等于0.0870000000000000000000在以下
行执行之后？

谢谢，
Nate

double d = 0.087000000000000008;
string s = string.Format（" ; {0：f22}"，d）;

Nathan Wiegman写道：

任何人都知道为什么s等于0.0870000000000000000000在以下
行执行后？
double d = 0.087000000000000008;
string s = string.Format（" {0：f22}"，d）;

double只有15-16位精度：第17位的8位是

输了。


-

www.midnightbeach.com

Hi,

Anyone know why "s" equals "0.0870000000000000000000" after the following
lines execute?

Thanks,
Nate

double d = 0.087000000000000008;
string s = string.Format("{0:f22}", d);

解决方案

"0870000000000000000000" has length of 22

0:f# -> Fixed point with # length, unspecified # is 2 i think
if you just want 0.87
then just use 0:f

"Nathan Wiegman" <Na***********@discussions.microsoft.com> wrote in message
news:45**********************************@microsof t.com...

Hi,

Anyone know why "s" equals "0.0870000000000000000000" after the following
lines execute?

Thanks,
Nate

double d = 0.087000000000000008;
string s = string.Format("{0:f22}", d);

typo

"if you just want 0.87" <- this should be 0.08

"Du" <vi*******@hotmail.com> wrote in message
news:IK********************@rogers.com...

"0870000000000000000000" has length of 22

0:f# -> Fixed point with # length, unspecified # is 2 i think
if you just want 0.87
then just use 0:f

"Nathan Wiegman" <Na***********@discussions.microsoft.com> wrote in
message news:45**********************************@microsof t.com...

Hi,

Anyone know why "s" equals "0.0870000000000000000000" after the following
lines execute?

Thanks,
Nate

double d = 0.087000000000000008;
string s = string.Format("{0:f22}", d);

Nathan Wiegman wrote:

Anyone know why "s" equals "0.0870000000000000000000" after the following
lines execute? double d = 0.087000000000000008;
string s = string.Format("{0:f22}", d);

double only has "15-16 digits" precision: the 8 in the 17th place is
lost.

--

www.midnightbeach.com

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